comment section fix

Author: 0zzy0sbourne

Experiment - 3/part3.asm

@@ -1,41 +1,38 @@
-/*
-    R10 is set to the address of arr, and R11 is set to the address of arr2.
+;----------------------------------------------
+;   R10 is set to the address of arr, and R11 is set to the address of arr2.
 
-    R12 is used as the index for the last element of arr (assuming that arr has 50 elements, 0-based index).
+;   R12 is used as the index for the last element of arr (assuming that arr has 50 elements, 0-based index).
 
-    The loop (reverseLoop) copies elements from the end of arr to the beginning of arr2, 
-    effectively reversing the order of the elements.
+;   The loop (reverseLoop) copies elements from the end of arr to the beginning of arr2, 
+;   effectively reversing the order of the elements.
 
-    After running this code, arr2 will contain the reverse order of the elements that were originally in arr. 
+;   After running this code, arr2 will contain the reverse order of the elements that were originally in arr. 
 
-    You can adjust the size and starting addresses of arr and arr2 based on your specific requirements.
-*/
-
-
-; Allocate space in memory for arr and arr2
-a r r . s p a c e 100
-a r r 2 . s p a c e 100
+;   You can adjust the size and starting addresses of arr and arr2 based on your specific requirements.
+;----------------------------------------------
 
 ; Initialize registers
 mov.w #arr, R10    ; Set R10 to the address of arr
 mov.w #arr2, R11   ; Set R11 to the address of arr2
 mov.w #49d, R12    ; Set R12 as the index for the last element of arr (0-based index)
 
 ; Start the loop to reverse arr and store it in arr2
-reverseLoop:
-    ; Copy the element from arr to arr2
-    mov.w 0(R10), R13   ; Load the element from arr
-    mov.w R13, 0(R11)   ; Store it in arr2
+reverseLoop ; Copy the element from arr to arr2
+            mov.w 0(R10), R13   ; Load the element from arr
+            mov.w R13, 0(R11)   ; Store it in arr2
 
-    ; Move the pointers
-    add #2d, R10    ; Move R10 to the next element in arr
-    sub #2d, R11    ; Move R11 to the previous position in arr2
+            ; Move the pointers
+            add #2d, R10    ; Move R10 to the next element in arr
+            sub #2d, R11    ; Move R11 to the previous position in arr2
 
-    ; Check if we have copied all elements
-    cmp.w R10, R11  ; Compare R10 with R11
-    jl reverseLoop  ; If R10 is less than R11, continue the loop
+            ; Check if we have copied all elements
+            cmp.w R10, R11  ; Compare R10 with R11
+            jl reverseLoop  ; If R10 is less than R11, continue the loop
 
 ; End of the program
 
 
+; Allocate space in memory for arr and arr2
+arr         .space 100
+arr2        .space 100