Implement int sqrt(int x).
Compute and return the square root of x, where x is guaranteed to be a non-negative integer.
Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.
Example 1:
Input: 4
Output: 2
Example 2:
Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since
the decimal part is truncated, 2 is returned.
int mySqrt(int x){
if(x == 1)
return 1;
int min = 0;
int max = x;
while(max - min > 1){
int middle = (max + min) / 2;
if(x / middle < middle)
max = middle;
else
min = middle;
}
return min;
}Runtime: 4 ms Memory Usage: 6.9 MB