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ClassificationOfSubgroups/Ch6_MaximalAbelianSubgroupClassEquation/S2_MaximalAbelianSubgroup.lean

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@@ -1771,6 +1771,7 @@ noncomputable def quot_MulEquiv_quot_of {F : Type*} [Field F] (A' G' : Subgroup
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simp_rw [hy''₂, hy'₂]
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)
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-- Need to split into smaller lemmas
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/- Theorem 2.3 (iv a) If A ∈ M and |A| is relatively prime to p, then we have [N_G (A) : A] ≤ 2. -/
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theorem index_normalizer_le_two {p : ℕ} [hp : Fact (Nat.Prime p)]
@@ -1811,7 +1812,7 @@ theorem index_normalizer_le_two {p : ℕ} [hp : Fact (Nat.Prime p)]
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have hA' : A' ∈ MaximalAbelianSubgroupsOf G' := by
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rw [iff_conj_MaximalAbelianSubgroupsOf_conj A' G' c, ← A_eq_conj_A', ← G_eq_conj_G']
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exact hA
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-- factor out lemma for lemma 2.3 iv b)
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have index_eq : ((A'.subgroupOf G').subgroupOf (A'.subgroupOf G').normalizer).index =
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((A.subgroupOf G).subgroupOf (A.subgroupOf G).normalizer).index := by
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rw [index_eq_card, index_eq_card]
@@ -1946,7 +1947,7 @@ then there is an element y of NG (A)\A such that, yxy⁻¹ = x⁻¹ for all x
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-/
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theorem of_index_normalizer_eq_two {F : Type*} [Field F] {p : ℕ }(A G : Subgroup SL(2,F))
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(hA : A ∈ MaximalAbelianSubgroupsOf G) (hA' : Nat.Coprime (Nat.card A) p)
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(hNA : A.normalizer.index = 2) (x : A) :
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(hNA : relIndex (A.subgroupOf G) (A.subgroupOf G).normalizer = 2) (x : A) :
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∃ y ∈ A.normalizer.carrier \ A, y * x * y⁻¹ = x⁻¹ := by sorry
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/-

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