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Copy path1219. Path with Maximum Gold.java
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40 lines (32 loc) · 1.02 KB
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Copy path1219. Path with Maximum Gold.java
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40 lines (32 loc) · 1.02 KB
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class Solution {
int max = 0;
public int getMaximumGold(int[][] grid) {
int n = grid.length;
int m = grid[0].length;
boolean vis[][] = new boolean[n][m];
for(int i = 0; i < n; i++)
{
for(int j = 0; j < m; j++)
{
if(grid[i][j] != 0)
dfs(grid, i, j, vis, 0, n, m);
}
}
return max;
}
void dfs(int[][] grid, int i, int j, boolean vis[][], int sum, int n, int m)
{
if(i < 0 || j < 0 || i >= n || j >= m || vis[i][j] == true || grid[i][j] == 0)
return;
// max = Math.max(max, sum);
sum += grid[i][j];
vis[i][j] = true;
dfs(grid, i+1, j, vis, sum, n, m);
dfs(grid, i-1, j, vis, sum, n, m);
dfs(grid, i, j+1, vis, sum, n, m);
dfs(grid, i, j-1, vis, sum, n, m);
max = Math.max(max, sum);
sum -= grid[i][j];
vis[i][j] = false;
}
}