Update pymath/power_of_i/README.md

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Author: BrianLusina

pymath/power_of_i/README.md

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 # Power of I
 
-i is the imaginary unit, it is defined by i²=−1i² = -1i²=−1, therefore it is a solution to x²+1=0x² + 1 = 0x²+1=0.
+i is the imaginary unit, defined by i² = −1; thus it is a solution to x² + 1 = 0.
 
 Your Task Complete the function pofi that returns iii to the power of a given non-negative integer in its simplest form,
 as a string (answer may contain i).