Merge pull request #180 from BrianLusina/feat/algorithms-graphs

feat(algorithms, graphs): min cost to make at least one valid path in a grid

Author: BrianLusina

DIRECTORY.md

@@ -143,6 +143,8 @@
       * [Test Max Area Of Island](https://github.com/BrianLusina/PythonSnips/blob/master/algorithms/graphs/maxareaofisland/test_max_area_of_island.py)
     * Min Cost To Supply
       * [Test Min Cost To Supply](https://github.com/BrianLusina/PythonSnips/blob/master/algorithms/graphs/min_cost_to_supply/test_min_cost_to_supply.py)
+    * Min Cost Valid Path
+      * [Test Min Cost To Make Valid Path](https://github.com/BrianLusina/PythonSnips/blob/master/algorithms/graphs/min_cost_valid_path/test_min_cost_to_make_valid_path.py)
     * Nearest Exit From Entrance In Maze
       * [Test Nearest Exit From Entrance](https://github.com/BrianLusina/PythonSnips/blob/master/algorithms/graphs/nearest_exit_from_entrance_in_maze/test_nearest_exit_from_entrance.py)
     * Network Delay Time

algorithms/graphs/min_cost_valid_path/README.md

@@ -0,0 +1,259 @@
+from typing import List
+import heapq
+from collections import deque
+import sys
+
+
+def min_cost_dp(grid: List[List[int]]) -> int:
+    if not grid:
+        return 0
+
+    num_rows = len(grid)
+    num_cols = len(grid[0])
+
+    min_changes = [[float("inf")] * num_cols for _ in range(num_rows)]
+    min_changes[0][0] = 0
+
+    while True:
+        # Store previous state to check for convergence
+        prev_state = [row[:] for row in min_changes]
+
+        # forward pass: check cells coming from left and top
+        for row in range(num_rows):
+            for col in range(num_cols):
+                # check cell above
+                if row > 0:
+                    min_changes[row][col] = min(
+                        min_changes[row][col],
+                        min_changes[row - 1][col]
+                        + (0 if grid[row - 1][col] == 3 else 1),
+                    )
+
+                # check cell to the left
+                if col > 0:
+                    min_changes[row][col] = min(
+                        min_changes[row][col],
+                        min_changes[row][col - 1]
+                        + (0 if grid[row][col - 1] == 1 else 1),
+                    )
+
+        # backward pass: check cells coming from right and bottom
+        for row in range(num_rows - 1, -1, -1):
+            for col in range(num_cols - 1, -1, -1):
+                # check cell below
+                if row < num_rows - 1:
+                    min_changes[row][col] = min(
+                        min_changes[row][col],
+                        min_changes[row + 1][col]
+                        + (0 if grid[row + 1][col] == 4 else 1),
+                    )
+
+                # Check cell to the right
+                if col < num_cols - 1:
+                    min_changes[row][col] = min(
+                        min_changes[row][col],
+                        min_changes[row][col + 1]
+                        + (0 if grid[row][col + 1] == 2 else 1),
+                    )
+
+        # if not changes were made in this operation, we've found optimal solution
+        if min_changes == prev_state:
+            break
+
+    return min_changes[num_rows - 1][num_cols - 1]
+
+
+def min_cost_dijkstra(grid: List[List[int]]) -> int:
+    if not grid:
+        return 0
+
+    dirs = [(0, 1), (0, -1), (1, 0), (-1, 0)]
+    num_rows = len(grid)
+    num_cols = len(grid[0])
+
+    # Min-heap ordered by cost. Each element is (cost, row, col)
+    # Using list as heap, elements are tuples
+    pq = [(0, 0, 0)]
+
+    cost_grid = [[float("inf")] * num_cols for _ in range(num_rows)]
+    cost_grid[0][0] = 0
+
+    while pq:
+        cost, row, col = heapq.heappop(pq)
+
+        # skip if we've found a better path to this cell
+        if cost_grid[row][col] != cost:
+            continue
+
+        # Try all 4 directions
+        for d, (dr, dc) in enumerate(dirs):
+            new_row = row + dr
+            new_col = col + dc
+
+            # Check if new position is valid
+            if 0 <= new_row < num_rows and 0 <= new_col < num_cols:
+                # add cost = 1 if we need to change direction
+                new_cost = cost + (d != (grid[row][col] - 1))
+
+                # update if we found a better path
+                if cost_grid[new_row][new_col] > new_cost:
+                    cost_grid[new_row][new_col] = new_cost
+                    heapq.heappush(pq, (new_cost, new_row, new_col))
+
+    return cost_grid[num_rows - 1][num_cols - 1]
+
+
+def min_cost_0_1_bfs(grid: List[List[int]]) -> int:
+    if not grid:
+        return 0
+    num_rows = len(grid)
+    num_cols = len(grid[0])
+    # Direction vectors: right, left, down, up (matching grid values 1,2,3,4)
+    dirs = [(0, 1), (0, -1), (1, 0), (-1, 0)]
+
+    cost_grid = [[float("inf")] * num_cols for _ in range(num_rows)]
+    cost_grid[0][0] = 0
+
+    # Use deque for 0-1 BFS - add zero cost moves to front, cost=1 to back
+    queue = deque([(0, 0)])
+
+    # Check if coordinates are within grid bounds
+    def is_valid(row: int, col: int) -> bool:
+        return 0 <= row < num_rows and 0 <= col < num_cols
+
+    while queue:
+        row, col = queue.popleft()
+        # Try all four directions
+        for dir_idx, (dx, dy) in enumerate(dirs):
+            new_row, new_col = row + dx, col + dy
+            cost = 0 if grid[row][col] == dir_idx + 1 else 1
+
+            # If position is valid and we found a better path
+            if (
+                is_valid(new_row, new_col)
+                and cost_grid[row][col] + cost < cost_grid[new_row][new_col]
+            ):
+                cost_grid[new_row][new_col] = cost_grid[row][col] + cost
+
+                # Add to back if cost=1, front if cost=0
+                if cost == 1:
+                    queue.append((new_row, new_col))
+                else:
+                    queue.appendleft((new_row, new_col))
+
+    return cost_grid[num_rows - 1][num_cols - 1]
+
+
+def min_cost_0_1_bfs_2(grid: List[List[int]]) -> int:
+    if not grid:
+        return 0
+    # Store the number of rows and columns of grid
+    num_rows, num_cols = len(grid), len(grid[0])
+
+    # Create a 2D array of size num_rows x num_cols, initializing all cells to the maximum integer value
+    cost_grid = [[sys.maxsize] * num_cols for _ in range(num_rows)]
+
+    # Helper function to check if the new cell is valid and its cost can be improved
+    def is_valid_and_improvable(row, col) -> bool:
+        return (
+            0 <= row < len(cost_grid)
+            and 0 <= col < len(cost_grid[0])
+            and cost_grid[row][col] != 0
+        )
+
+    # Create a deque and push the starting cell (0, 0) to the front
+    dq = deque()
+    dq.appendleft((0, 0))
+
+    # Set its cost in cost_grid to 0
+    cost_grid[0][0] = 0
+
+    # Define an array representing the four possible movement directions
+    dirs = [[0, 1], [0, -1], [1, 0], [-1, 0]]
+
+    # Enter a loop that continues as long as the deque is not empty
+    while dq:
+        # Pop the front cell from the deque and store its coordinates in row and col
+        row, col = dq.popleft()
+
+        # Loop through each of the four directions in dirs
+        for d in range(4):
+            # Compute the coordinates of the adjacent cell
+            new_row = row + dirs[d][0]
+            new_col = col + dirs[d][1]
+
+            # Check if the new cell is valid and its cost can be improved
+            if is_valid_and_improvable(new_row, new_col):
+                # Calculate the movement cost
+                cost = 1 if grid[row][col] != (d + 1) else 0
+
+                # Check whether the new cost is less than the current cost at the adjacent cell
+                if cost_grid[row][col] + cost < cost_grid[new_row][new_col]:
+                    # Update the cost of the adjacent cell
+                    cost_grid[new_row][new_col] = cost_grid[row][col] + cost
+
+                    if cost == 1:
+                        # Push the new cell to the back
+                        dq.append((new_row, new_col))
+                    else:
+                        # Push the new cell to the front
+                        dq.appendleft((new_row, new_col))
+
+    # Return the minimum cost stored at the bottom-right cell
+    return cost_grid[num_rows - 1][num_cols - 1]
+
+
+def min_cost_dfs_and_bfs(grid: List[List[int]]) -> int:
+    if not grid:
+        return 0
+    # Direction vectors: right, left, down, up (matching grid values 1,2,3,4)
+    dirs = [(0, 1), (0, -1), (1, 0), (-1, 0)]
+    num_rows = len(grid)
+    num_cols = len(grid[0])
+    cost = 0
+
+    # Track minimum cost to reach each cell
+    cost_grid = [[float("inf")] * num_cols for _ in range(num_rows)]
+
+    queue = deque()
+
+    # DFS to explore all reachable cells with current cost
+    def dfs(
+        row: int,
+        col: int,
+        cost: int,
+    ) -> None:
+        if not is_unvisited(row, col):
+            return
+
+        cost_grid[row][col] = cost
+        queue.append((row, col))
+
+        # Follow the arrow direction without cost increase
+        next_dir = grid[row][col] - 1
+        dx, dy = dirs[next_dir]
+        dfs(row + dx, col + dy, cost)
+
+    # Check if cell is within bounds and unvisited
+    def is_unvisited(row: int, col: int) -> bool:
+        return (
+            0 <= row < len(cost_grid)
+            and 0 <= col < len(cost_grid[0])
+            and cost_grid[row][col] == float("inf")
+        )
+
+    dfs(0, 0, cost)
+
+    # BFS part - process cells level by level with increasing cost
+    while queue:
+        cost += 1
+        level_size = len(queue)
+
+        for _ in range(level_size):
+            row, col = queue.popleft()
+
+            # Try all 4 directions for next level
+            for dir_idx, (dx, dy) in enumerate(dirs):
+                dfs(row + dx, col + dy, cost)
+
+    return cost_grid[num_rows - 1][num_cols - 1]