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[level 3] Title: 부서별 평균 연봉 조회하기, Time: , Memory: undefined -BaekjoonHub
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‎프로그래머스/3/284529. 부서별 평균 연봉 조회하기/README.md‎

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# [level 3] 부서별 평균 연봉 조회하기 - 284529
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[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/284529)
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### 성능 요약
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메모리: undefined, 시간:
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### 구분
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코딩테스트 연습 > GROUP BY
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### 채점결과
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합계: 100.0 / 100.0
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### 제출 일자
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2025년 07월 03일 12:53:40
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### 문제 설명
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<p><code>HR_DEPARTMENT</code> 테이블은 회사의 부서 정보를 담은 테이블입니다. <code>HR_DEPARTMENT</code> 테이블의 구조는 다음과 같으며 <code>DEPT_ID</code>, <code>DEPT_NAME_KR</code>, <code>DEPT_NAME_EN</code>, <code>LOCATION</code>은 각각 부서 ID, 국문 부서명, 영문 부서명, 부서 위치를 의미합니다.</p>
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<table class="table">
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<thead><tr>
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<th>Column name</th>
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<th>Type</th>
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<th>Nullable</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>DEPT_ID</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>DEPT_NAME_KR</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>DEPT_NAME_EN</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>LOCATION</td>
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<td>VARCHAR</td>
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<td>FLASE</td>
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</tr>
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</tbody>
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</table>
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<p><code>HR_EMPLOYEES</code> 테이블은 회사의 사원 정보를 담은 테이블입니다. <code>HR_EMPLOYEES</code> 테이블의 구조는 다음과 같으며 <code>EMP_NO</code>, <code>EMP_NAME</code>, <code>DEPT_ID</code>, <code>POSITION</code>, <code>EMAIL</code>, <code>COMP_TEL</code>, <code>HIRE_DATE</code>, <code>SAL</code>은 각각 사번, 성명, 부서 ID, 직책, 이메일, 전화번호, 입사일, 연봉을 의미합니다.</p>
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<table class="table">
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<thead><tr>
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<th>Column name</th>
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<th>Type</th>
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<th>Nullable</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>EMP_NO</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>EMP_NAME</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>DEPT_ID</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>POSITION</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>EMAIL</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>COMP_TEL</td>
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<td>VARCHAR</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>HIRE_DATE</td>
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<td>DATE</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>SAL</td>
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<td>NUMBER</td>
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<td>FALSE</td>
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</tr>
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</tbody>
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</table>
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<hr>
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<h5>문제</h5>
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<p><code>HR_DEPARTMENT</code>와 <code>HR_EMPLOYEES</code> 테이블을 이용해 부서별 평균 연봉을 조회하려 합니다. 부서별로 부서 ID, 영문 부서명, 평균 연봉을 조회하는 SQL문을 작성해주세요.</p>
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<p>평균연봉은 소수점 첫째 자리에서 반올림하고 컬럼명은 <code>AVG_SAL</code>로 해주세요.<br>
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결과는 부서별 평균 연봉을 기준으로 내림차순 정렬해주세요.</p>
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<hr>
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<h5>예시</h5>
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<p><code>HR_DEPARTMENT</code> 테이블이 다음과 같고</p>
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<table class="table">
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<thead><tr>
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<th>DEPT_ID</th>
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<th>DEPT_NAME_KR</th>
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<th>DEPT_NAME_EN</th>
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<th>LOCATION</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>D0005</td>
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<td>재무팀</td>
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<td>Finance</td>
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<td>그렙타워 5층</td>
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</tr>
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<tr>
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<td>D0006</td>
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<td>구매팀</td>
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<td>Purchasing</td>
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<td>그렙타워 5층</td>
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</tr>
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<tr>
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<td>D0007</td>
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<td>마케팅팀</td>
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<td>Marketing</td>
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<td>그렙타워 6층</td>
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</tr>
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</tbody>
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</table>
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<p><code>HR_EMPLOYEES</code> 테이블이 다음과 같을 때</p>
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<table class="table">
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<thead><tr>
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<th>EMP_NO</th>
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<th>EMP_NAME</th>
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<th>DEPT_ID</th>
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<th>POSITION</th>
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<th>EMAIL</th>
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<th>COMP_TEL</th>
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<th>HIRE_DATE</th>
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<th>SAL</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>2019003</td>
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<td>한동희</td>
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<td>D0005</td>
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<td>팀장</td>
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<td><a href="mailto:donghee_han@grep.com" target="_blank" rel="noopener">donghee_han@grep.com</a></td>
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<td>031-8000-1122</td>
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<td>2019-03-01</td>
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<td>57000000</td>
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</tr>
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<tr>
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<td>2020032</td>
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<td>한명지</td>
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<td>D0005</td>
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<td>팀원</td>
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<td><a href="mailto:mungji_han@grep.com" target="_blank" rel="noopener">mungji_han@grep.com</a></td>
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<td>031-8000-1123</td>
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<td>2020-03-01</td>
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<td>52000000</td>
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</tr>
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<tr>
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<td>2022003</td>
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<td>김보라</td>
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<td>D0005</td>
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<td>팀원</td>
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<td><a href="mailto:bora_kim@grep.com" target="_blank" rel="noopener">bora_kim@grep.com</a></td>
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<td>031-8000-1126</td>
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<td>2022-03-01</td>
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<td>47000000</td>
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</tr>
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<tr>
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<td>2018005</td>
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<td>이재정</td>
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<td>D0006</td>
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<td>팀장</td>
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<td><a href="mailto:jaejung_lee@grep.com" target="_blank" rel="noopener">jaejung_lee@grep.com</a></td>
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<td>031-8000-1127</td>
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<td>2018-03-01</td>
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<td>60000000</td>
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</tr>
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<tr>
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<td>2019032</td>
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<td>윤성희</td>
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<td>D0006</td>
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<td>팀원</td>
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<td><a href="mailto:sunghee_yoon@grep.com" target="_blank" rel="noopener">sunghee_yoon@grep.com</a></td>
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<td>031-8000-1128</td>
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<td>2019-03-01</td>
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<td>57000000</td>
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</tr>
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<tr>
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<td>2020009</td>
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<td>송영섭</td>
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<td>D0006</td>
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<td>팀원</td>
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<td><a href="mailto:yungseop_song@grep.com" target="_blank" rel="noopener">yungseop_song@grep.com</a></td>
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<td>031-8000-1130</td>
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<td>2020-03-01</td>
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<td>51000000</td>
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</tr>
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<tr>
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<td>2021006</td>
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<td>이성주</td>
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<td>D0006</td>
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<td>팀원</td>
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<td><a href="mailto:sungju_lee@grep.com" target="_blank" rel="noopener">sungju_lee@grep.com</a></td>
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<td>031-8000-1131</td>
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<td>2021-03-01</td>
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<td>49000000</td>
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</tr>
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<tr>
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<td>2018004</td>
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<td>이주리</td>
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<td>D0007</td>
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<td>팀장</td>
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<td><a href="mailto:joori_lee@grep.com" target="_blank" rel="noopener">joori_lee@grep.com</a></td>
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<td>031-8000-1132</td>
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<td>2018-03-01</td>
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<td>61000000</td>
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</tr>
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<tr>
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<td>2020012</td>
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<td>김사랑</td>
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<td>D0007</td>
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<td>팀원</td>
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<td><a href="mailto:sarang_kim@grep.com" target="_blank" rel="noopener">sarang_kim@grep.com</a></td>
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<td>031-8000-1133</td>
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<td>2020-03-01</td>
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<td>54000000</td>
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</tr>
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<tr>
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<td>2021018</td>
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<td>김히라</td>
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<td>D0007</td>
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<td>팀원</td>
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<td><a href="mailto:heera_kim@grep.com" target="_blank" rel="noopener">heera_kim@grep.com</a></td>
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<td>031-8000-1136</td>
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<td>2021-03-01</td>
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<td>49000000</td>
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</tr>
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</tbody>
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</table>
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<p>SQL을 실행하면 다음과 같이 출력되어야 합니다.</p>
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<table class="table">
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<thead><tr>
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<th>DEPT_ID</th>
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<th>DEPT_NAME_EN</th>
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<th>AVG_SAL</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>D0007</td>
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<td>Marketing</td>
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<td>54666667</td>
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</tr>
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<tr>
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<td>D0006</td>
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<td>Purchasing</td>
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<td>54250000</td>
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</tr>
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<tr>
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<td>D0005</td>
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<td>Finance</td>
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<td>52000000</td>
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</tr>
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</tbody>
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</table>
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> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges

‎프로그래머스/3/284529. 부서별 평균 연봉 조회하기/부서별 평균 연봉 조회하기.sql‎

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select e.dept_id, d.dept_name_en, round(AVG(e.SAL), 0) as avg_sal
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from hr_employees as e
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join hr_department as d
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on d.dept_id = e.dept_id
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group by d.dept_id
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order by avg_sal desc;

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