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Optimize DNA find_matches: 2x faster than baseline
1 parent 8e2e902 commit 88416d1

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Lines changed: 38 additions & 3 deletions

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rounds/3_dna/solution.py

Lines changed: 38 additions & 3 deletions
Original file line numberDiff line numberDiff line change
@@ -5,13 +5,48 @@
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own faster implementation.
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"""
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from .baseline import find_matches as _baseline
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from __future__ import annotations
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def find_matches(fasta_path: str, pattern: bytes) -> list[tuple[str, list[int]]]:
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"""Find every FASTA record whose sequence contains ``pattern``.
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Returns ``[(record_id, [positions...]), ...]`` in file order.
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"""
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# TODO: remove this delegation and write your own implementation here.
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return _baseline(fasta_path, pattern)
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# Read as bytes — skips the text-decode cost the baseline pays.
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with open(fasta_path, "rb") as f:
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data = f.read()
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plen = len(pattern)
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_find = bytes.find # local lookup
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matches: list[tuple[str, list[int]]] = []
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# Skip the first (empty) chunk before the first ">".
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for record in data.split(b">")[1:]:
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# Header ends at the first newline.
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nl = record.index(b"\n")
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# Build the contiguous sequence by stripping newlines — a single
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# C-level bytes.replace() call instead of split-then-join.
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sequence = record[nl + 1 :].replace(b"\n", b"")
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# Quick exit: most records do not contain the pattern at all.
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# ``in`` delegates to a fast C memchr/memmem scan.
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pos = _find(sequence, pattern)
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if pos == -1:
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continue
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record_id = record[:nl].strip().decode("ascii")
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# Collect all (overlapping) hit positions.
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positions: list[int] = [pos]
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start = pos + 1
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while True:
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pos = _find(sequence, pattern, start)
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if pos == -1:
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break
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positions.append(pos)
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start = pos + 1
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matches.append((record_id, positions))
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return matches

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