fix(formatter): use primitive type instead of schema name in get_response_type (#3916)

When a named component schema has a primitive type (e.g. type: string),
get_response_type() used schema_name() directly, emitting the schema name
as a versioned type — but no type is generated for primitive schemas,
causing a compile error in generated examples.

Fix: check simple_type() first; if the schema resolves to a primitive,
use that type directly. Consistent with how type_to_typescript() already
guards against this case.

Co-authored-by: Claude Sonnet 4.6 <noreply@anthropic.com>

Author: walidcavelius

.generator/src/generator/formatter.py

@@ -451,6 +451,12 @@ def get_response_type(schema, version):
             name = simple_type(nested_schema)
         api_response_type = f"{name}[]"
     else:
+        primitive = simple_type(response_schema)
         name = schema_name(response_schema)
-        api_response_type = f"{version}.{name}" if name else simple_type(response_schema)
+        if name and not primitive:
+            api_response_type = f"{version}.{name}"
+        else:
+            # Named primitive schemas (e.g. type: string) don't produce a class —
+            # use the primitive type directly.
+            api_response_type = primitive
     return api_response_type