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doc(LinearAlgebra): fix typos (leanprover-community#37341)
These typos were found and fixed by Claude Opus 4.6.
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Mathlib/LinearAlgebra/Center.lean

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@@ -21,13 +21,13 @@ the center of `Module.End R V`.
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In what follows, `V` is assumed to be a free `R`-module.
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* `LinearMap.commute_transvections_iff_of_basis`:
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if an endomorphism `f : V →ₗ[R] V` commutes with every elementary transvections
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(in a given basis), then it is an homothety with central ratio.
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if an endomorphism `f : V →ₗ[R] V` commutes with every elementary transvection
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(in a given basis), then it is a homothety with central ratio.
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(Assumes that the basis is provided and has a non trivial set of indices.)
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* `LinearMap.exists_eq_smul_id_of_forall_notLinearIndependent`:
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over a commutative ring `R` which is a domain, an endomorphism `f : V →ₗ[R] V`
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of a free domain such that `v` and `f v` are not linearly independent,
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of a free module such that `v` and `f v` are not linearly independent,
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for all `v : V`, is a homothety.
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* `LinearMap.exists_mem_center_apply_eq_smul_of_forall_notLinearIndependent`:
@@ -41,7 +41,7 @@ In what follows, `V` is assumed to be a free `R`-module.
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Note. In the noncommutative case, the last two results do not hold
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when the rank is equal to 1. Indeed, right multiplications
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with noncentral ratio of the `R`-module `R` satisfy the property
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that `f v` and `v` are linearly independent, for all `v : V`,
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that `f v` and `v` are linearly dependent, for all `v : V`,
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but they are not left multiplication by some element.
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-/
@@ -92,17 +92,17 @@ theorem commute_transvections_iff_of_basis
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set_option backward.isDefEq.respectTransparency false in
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/-- Over a domain, an endomorphism `f` of a free module `V`
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of rank ≠ 1 such that `f v` and `v` are colinear, for all `v : V`,
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of rank ≠ 1 such that `f v` and `v` are collinear, for all `v : V`,
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consists of homotheties with central ratio.
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In the commutative case, use `LinearMap.exists_eq_smul_id`.
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This is a variant of `LinearMap.exists_mem_center_apply_smul`
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which switches the use `StrongRankInduction` and `finrank`
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which switches the use of `StrongRankInduction` and `finrank`
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for the cardinality of a given basis.
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When `finrank R V = 1`, up to a linear equivalence `V ≃ₗ[R] R`,
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then any `f` is *right*-multiplication by some `a : K`,
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then any `f` is *right*-multiplication by some `a : R`,
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but not necessarily *left*-multiplication by an element of the center of `R`. -/
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theorem exists_mem_center_apply_eq_smul_of_forall_notLinearIndependent_of_basis
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[Ring R] [IsDomain R] [AddCommGroup V] [Module R V]
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set_option backward.isDefEq.respectTransparency false in
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/-- Over a domain `R`, an endomorphism `f` of a free module `V`
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of rank ≠ 1 such that `f v` and `v` are colinear, for all `v : V`,
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of rank ≠ 1 such that `f v` and `v` are collinear, for all `v : V`,
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consists of homotheties with central ratio.
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When `R`does not satisfy `StrongRankCondition`, use
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When `R` does not satisfy `StrongRankCondition`, use
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`LinearMap.exists_mem_center_apply_eq_smul_of_basis`.
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When `finrank R V = 1`, up to a linear equivalence `V ≃ₗ[R] R`,
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then any `f` is *right*-multiplication by some `a : K`,
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then any `f` is *right*-multiplication by some `a : R`,
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but not necessarily *left*-multiplication by an element of the center of `R`. -/
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theorem exists_mem_center_apply_eq_smul_of_forall_notLinearIndependent
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[Ring R] [IsDomain R] [StrongRankCondition R]
@@ -210,7 +210,7 @@ theorem exists_mem_center_apply_eq_smul_of_forall_notLinearIndependent
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exact exists_mem_center_apply_eq_smul_of_forall_notLinearIndependent_of_basis b h
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/-- Over a commutative domain, an endomorphism `f` of a free module `V`
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such that `f v` and `v` are colinear, for all `v : V`,
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such that `f v` and `v` are collinear, for all `v : V`,
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consists of homotheties. -/
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theorem exists_eq_smul_id_of_forall_notLinearIndependent
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[CommRing R] [IsDomain R] [AddCommGroup V] [Module R V] [Free R V] {f : V →ₗ[R] V}

Mathlib/LinearAlgebra/JordanChevalley.lean

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@@ -17,10 +17,10 @@ sufficient condition for there to exist a nilpotent endomorphism `n` and a semis
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`s`, such that `f = n + s` and both `n` and `s` are polynomial expressions in `f`.
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The condition is that there exists a separable polynomial `P` such that the endomorphism `P(f)` is
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nilpotent. This condition is always satisfied when the coefficients are a perfect field.
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nilpotent. This condition is always satisfied when the coefficient field is perfect.
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The proof given here uses Newton's method and is taken from Chambert-Loir's notes:
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[Algebre](http://webusers.imj-prg.fr/~antoine.chambert-loir/enseignement/2022-23/agreg/algebre.pdf)
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[Algèbre](http://webusers.imj-prg.fr/~antoine.chambert-loir/enseignement/2022-23/agreg/algebre.pdf)
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## Main definitions / results:
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