Add comment explaining Kotlin split() preserves trailing empty segments unlike Java

Co-authored-by: Goooler <10363352+Goooler@users.noreply.github.com>

Author: Copilot

src/main/kotlin/com/github/jengelman/gradle/plugins/shadow/internal/Relocators.kt

@@ -13,7 +13,9 @@ internal fun Set<Relocator>.mapName(
   mapLiterals: Boolean = false,
   onModified: () -> Unit,
 ): String {
-  // Maybe a list of types.
+  // Maybe a list of types. Unlike Java's String.split(), Kotlin's split() with the default
+  // limit = 0 preserves trailing empty segments, so descriptor strings ending with ';'
+  // (e.g. "Lorg/package/ClassA;") round-trip correctly.
   val newName = name.split(';').joinToString(";") { realMap(it, mapLiterals) }
   if (newName != name) {
     onModified()