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51 lines (38 loc) · 1.83 KB
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// Predict and explain first...
// Predict the output of the following code:
// =============> Write your prediction here
// The output will always be 3 for all cases. Even though
// arguments are passed to the function, it lacks parameter
// to receive them. Therefore, the function defaults to using
// the global scope constant num = 103 every time it runs.
// const num = 103;
// function getLastDigit() {
// return num.toString().slice(-1);
// }
// console.log(`The last digit of 42 is ${getLastDigit(42)}`);
// console.log(`The last digit of 105 is ${getLastDigit(105)}`);
// console.log(`The last digit of 806 is ${getLastDigit(806)}`);
// Now run the code and compare the output to your prediction
// =============> write the output here
// The output is:
// The last digit of 42 is 3
// The last digit of 105 is 3
// The last digit of 806 is 3
// Explain why the output is the way it is
// =============> write your explanation here
// The function getLastDigit is not working properly because
// it is hardcoded to use the global constant num. Since
// the function definition does not include any parameters,
// it ignores the arguments (42, 105, 806) passed during the
// call. As a result, it always calculates the last digit of 103, which is 3
// Finally, correct the code to fix the problem
// =============> write your new code here
const num = 103; //this now is a ghost variable and is not used in the function
function getLastDigit(value) {
return value.toString().slice(-1);
}
console.log(`The last digit of 42 is ${getLastDigit(42)}`);
console.log(`The last digit of 105 is ${getLastDigit(105)}`);
console.log(`The last digit of 806 is ${getLastDigit(806)}`);
// This program should tell the user the last digit of each number.
// Explain why getLastDigit is not working properly - correct the problem