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Merge pull request #319 from KxlSys/bolt-perf-matching-array-consolidation-4431554792924675838
⚡ Bolt: Optimize matching algorithms by consolidating array methods
2 parents bef1246 + 35f599d commit 4782712

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Lines changed: 18 additions & 19 deletions

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.jules/bolt.md

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@@ -21,7 +21,6 @@
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## 2024-07-10 - O(n) Single Pass Data Aggregation
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**Learning:** Using chained array methods (e.g. `.map().filter()`, `.flatMap()`, and repeated `.filter()` over the same large list like `profiles`) leads to redundant O(n) passes over data and allocates unnecessary intermediate arrays. This blocks the main thread longer than necessary when calculating basic statistics like `uniqueCities`, `uniqueTechs`, or total counts.
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**Action:** Consolidate statistical aggregations over large object arrays into a single O(n) `for` loop that updates multiple accumulators (like `Set` objects and primitive counters) in one pass, thereby improving performance and reducing memory overhead.
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## 2024-07-18 - Component Map Memoization Pattern
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**Learning:** In React components with highly interactive state (like buttons triggering local state changes such as `visibleCount`), mapping over raw datasets to create derived UI objects outside of a `useMemo` block leads to unnecessary O(N) object allocations and garbage collection on every render.
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**Action:** When a component derives lists from props or state for rendering, wrap the mapping or filtering logic inside `useMemo` to cache the result, recalculating only when the underlying data changes, thereby freeing up the main thread from redundant object allocations.
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## 2024-07-20 - Consolidate array operations in matching algorithms
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**Learning:** Chaining multiple array methods (`.map().filter()`, `.flatMap()`) creates unnecessary intermediate arrays and O(N) passes over the data.
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**Action:** Use a single `reduce` or `for` loop with multiple accumulators to filter and transform the data simultaneously before sorting. This improves performance for data aggregation, particularly on large arrays like projects or candidates.

src/lib/matching.ts

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@@ -46,18 +46,19 @@ export function calculateMatches(
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): MatchResult[] {
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// ⚡ Bolt: Pre-calculate the current user's tech stack as a Set to avoid O(N*M) lookups
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const currentUserTechsSet = new Set(currentUser.tech_stack);
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const complementary = COMPLEMENTARY_ROLES[currentUser.role_type] || [];
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const levelMap = { junior: 1, mid: 2, senior: 3 };
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const results: MatchResult[] = [];
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// ⚡ Bolt: Consolidate map and filter into a single reduce pass
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const results = candidates.reduce<MatchResult[]>((acc, candidate) => {
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// ⚡ Bolt: Consolidate .filter().map().filter() into a single O(n) loop to reduce allocations
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for (let i = 0; i < candidates.length; i++) {
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const candidate = candidates[i];
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if (candidate.id === currentUser.id || !candidate.open_to_collaboration) {
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return acc;
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continue;
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}
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let score = 0;
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const reasons: string[] = [];
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const complementary = COMPLEMENTARY_ROLES[currentUser.role_type] || [];
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if (complementary.includes(candidate.role_type)) {
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score += 30;
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reasons.push("Competences complementaires");
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reasons.push("Meme ville");
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}
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const levelMap = { junior: 1, mid: 2, senior: 3 };
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const diff = Math.abs(
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levelMap[currentUser.experience_level] -
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levelMap[candidate.experience_level]
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}
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if (score > 0) {
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acc.push({ profile: candidate, score: Math.min(score, 100), reasons });
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results.push({ profile: candidate, score: Math.min(score, 100), reasons });
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}
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return acc;
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}, []);
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}
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return results.sort((a, b) => b.score - a.score);
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}
@@ -111,9 +111,11 @@ export function calculateProjectMatches(
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// ⚡ Bolt: Pre-calculate the lowercase tech stack of the profile to avoid re-lowercasing
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// it for every single tech in every single project.
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const profileTechsLower = profile.tech_stack.map((t) => t.toLowerCase());
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const results: ProjectMatch[] = [];
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// ⚡ Bolt: Consolidate map and filter into a single reduce pass
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const results = projects.reduce<ProjectMatch[]>((acc, project) => {
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// ⚡ Bolt: Consolidate .map().filter() into a single O(n) loop to reduce intermediate allocations
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for (let i = 0; i < projects.length; i++) {
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const project = projects[i];
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let score = 0;
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const reasons: string[] = [];
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}
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if (score > 0) {
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acc.push({ project, score: Math.min(score, 100), reasons });
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results.push({ project, score: Math.min(score, 100), reasons });
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}
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return acc;
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}, []);
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}
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return results.sort((a, b) => b.score - a.score);
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}

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