Medium
Given an integer array nums of unique elements, return all possible subsets (the power set).
The solution set must not contain duplicate subsets. Return the solution in any order.
Example 1:
Input: nums = [1,2,3]
Output: [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]
Example 2:
Input: nums = [0]
Output: [[],[0]]
Constraints:
1 <= nums.length <= 10-10 <= nums[i] <= 10- All the numbers of
numsare unique.
# @param {Integer[]} nums
# @return {Integer[][]}
def subsets(nums)
res = []
subsets = []
dfs_subsets(0, nums, subsets, res)
res
end
def dfs_subsets(i, nums, subsets, res)
return res.append(subsets.clone()) if i >= nums.length
subsets.append(nums[i])
dfs_subsets(i + 1, nums, subsets, res)
subsets.pop()
dfs_subsets(i + 1, nums, subsets, res)
end