README.md

subf

Subtract two single-precision floating-point numbers.

Usage

var subf = require( '@stdlib/number/float32/base/sub' );

subf( x, y )

Subtracts two single-precision floating-point numbers.

var v = subf( -1.0, 5.0 );
// returns -6.0

v = subf( 2.0, 5.0 );
// returns -3.0

v = subf( 0.0, 5.0 );
// returns -5.0

v = subf( -0.0, 0.0 );
// returns -0.0

v = subf( NaN, NaN );
// returns NaN

Examples

var discreteUniform = require( '@stdlib/random/array/discrete-uniform' );
var logEachMap = require( '@stdlib/console/log-each-map' );
var subf = require( '@stdlib/number/float32/base/sub' );

var x = discreteUniform( 100, -50, 50 );
var y = discreteUniform( 100, -50, 50 );

logEachMap( '%d - %d = %d', x, y, subf );

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C APIs

Usage

#include "stdlib/number/float32/base/sub.h"

stdlib_base_float32_sub( x, y )

Subtracts two single-precision floating-point numbers.

float v = stdlib_base_float32_sub( -5.0f, 2.0f );
// returns -7.0f

The function accepts the following arguments:

• x: [in] float first input value.
• y: [in] float second input value.

float stdlib_base_float32_sub( const float x, const float y );

Examples

#include "stdlib/number/float32/base/sub.h"
#include <stdio.h>

int main( void ) {
    const float x[] = { 3.14f, -3.14f, 0.0f, 0.0f/0.0f };
    const float y[] = { 3.14f, -3.14f, -0.0f, 0.0f/0.0f };

    float z;
    int i;
    for ( i = 0; i < 4; i++ ) {
        z = stdlib_base_float32_sub( x[ i ], y[ i ] );
        printf( "%f - %f = %f\n", x[ i ], y[ i ], z );
    }
}

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See Also

• @stdlib/number/float32/base/add: compute the sum of two single-precision floating-point numbers.
• @stdlib/number/float32/base/div: divide two single-precision floating-point numbers.
• @stdlib/number/float32/base/mul: multiply two single-precision floating-point numbers.
• @stdlib/number/float64/base/sub: subtract two double-precision floating-point numbers.