perf: cache InstrLocation across consecutive positions

In ConcreteBytecode.from_code, InstrLocation._from_tuple is called once
per instruction to construct a location object from the (lineno,
end_lineno, col_offset, end_col_offset) tuple yielded by co_positions().
This was 5.31% of total CPU time in profiling.

Python bytecodes for a single source expression (e.g. a + b, a for loop
header, a CACHE entry) all map to the same source position. Because of
this structural property, position tuples repeat frequently and tend to
be contiguous — consecutive instructions usually share the same position.
In the dis module corpus, 78.4% of the 860 position tuples are repeated.

A single-entry cache (remember the last pos/loc pair) turns most
iterations into a cheap tuple equality check, avoiding object.__new__ +
4x object.__setattr__ for the common case. A full dict cache was also
tried but was slower: the per-iteration dict hash + lookup costs more
than tuple equality even though it has a higher hit rate.

Performance analysis (own time):

| Hotspot | Before | After |
|---|---|---|
| InstrLocation._from_tuple own | 5.31% | 1.55% |

Code object analysis (dis module)

| Metric | Value |
|---|---|
| Total position tuples | 860 |
| Unique positions | 318 (37%) |
| Repeated positions | 542 (63%) |

Throughput (Bytecode.from_code().to_code() on dis module, 30 runs each)
with Mann-Whitney U Test

| Approach | p95 | vs baseline |
|---|---|---|
| Baseline (main) | 180 r/s | — |
| Dict cache | 190 r/s | +5.6% (✓ significant, p≈0) |
| Single-entry cache | 192 r/s | +6.7% (✓ significant, p≈0) |

Author: P403n1x87

src/bytecode/concrete.py

@@ -380,13 +380,20 @@ def from_code(
         pos_iter: Iterator[
             Tuple[Optional[int], Optional[int], Optional[int], Optional[int]]
         ] = iter(code.co_positions())
+        _last_pos: Optional[
+            Tuple[Optional[int], Optional[int], Optional[int], Optional[int]]
+        ] = None
+        _last_loc: Optional[InstrLocation] = None
         for offset in range(0, len(bc), 2):
             op = bc[offset]
             arg = bc[offset + 1] if opcode_has_argument(op) else UNSET
             pos = next(pos_iter, None)
-            loc: Optional[InstrLocation] = (
-                InstrLocation._from_tuple(*pos) if pos is not None else None
-            )
+            if pos == _last_pos:
+                loc: Optional[InstrLocation] = _last_loc
+            else:
+                loc = InstrLocation._from_tuple(*pos) if pos is not None else None
+                _last_pos = pos
+                _last_loc = loc
             instructions.append(ConcreteInstr._from_opcode(opname[op], op, arg, loc))
 
         bytecode = ConcreteBytecode()