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Solution.java
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46 lines (42 loc) · 1.58 KB
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/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public int findTilt(TreeNode root) {
int tilt = 0;
List<TreeNode> stack = new ArrayList<TreeNode>();
Map<TreeNode, Boolean> leftTraveredMap = new HashMap<TreeNode, Boolean>();
Map<TreeNode, Boolean> rightTraveredMap = new HashMap<TreeNode, Boolean>();
Map<TreeNode, Integer> sumMap = new HashMap<TreeNode, Integer>();
if (root != null) stack.add(root);
while (stack.size() > 0) {
TreeNode node = stack.get(stack.size() - 1);
if (node.left != null && leftTraveredMap.get(node) == null) {
leftTraveredMap.put(node, true);
stack.add(node.left);
} else if (node.right != null && rightTraveredMap.get(node) == null) {
rightTraveredMap.put(node, true);
stack.add(node.right);
} else {
stack.remove(stack.size() - 1);
int leftSum = 0;
if (sumMap.get(node.left) != null) {
leftSum = sumMap.get(node.left);
}
int rightSum = 0;
if (sumMap.get(node.right) != null) {
rightSum = sumMap.get(node.right);
}
sumMap.put(node, node.val + leftSum + rightSum);
tilt += Math.abs(leftSum - rightSum);
}
}
return tilt;
}
}