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D_HowManyArrays.cpp
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105 lines (92 loc) · 3.82 KB
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// ਹਰਅਸੀਸ ਸਿੰਘ
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define ff first
#define ss second
#define infinity 8999999999999999999
#define sz(v) ((int)(v).size())
#define all(v) (v).begin(),(v).end()
#define MOD_DEFINE const int MOD = 1e9 + 7;
#define endl '\n'
#define int long long
#define pii pair<int, int>
#define vi vector<int>
#define pb(n) push_back((n))
#define mii map<int, int>
#define umii unordered_map<int, int>
#define l(var, initial, final) for(int var=initial; var < final; var++)
#define cout std::cout
#define cin std::cin
#define pqb priority_queue<int>
#define pqs priority_queue<int, vi, greater<int>>
#define fps(x, y) fixed<<setprecision(y)<<x
typedef long long ll;
typedef vector<pii> vpii;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds;
void prn() { }
template<typename T1, typename T2> istream &operator >> (istream& in, pair<T1, T2> &a){in >> a.ff >> a.ss; return in;}
template<typename T1, typename T2> ostream &operator << (ostream& out, pair<T1, T2> a){out << a.ff << ' ' << a.ss; return out;}
template<typename T, typename T1> T amax(T &a, T1 b){if(b > a) a = b; return a;}
template<typename T, typename T1> T amin(T &a, T1 b){if(b < a) a = b; return a;}
template<typename T> istream& operator>>(istream &in, vector<T> &v) { for (auto &x : v) in >> x; return in;}
template<typename T> ostream& operator<<(ostream &out, vector<T> &v) {out << "{ "; for (auto &x : v) out << x << " "; out << "}\n"; return out;}
template<typename T, typename... Args> void prn(T x, Args... args) {cout << x << " "; prn(args...);}
template<typename Iterable> void prnIter(const Iterable& ITER, ostream&out = cout){ auto x = ITER.begin(); out << "{ "; for (; x != ITER.end(); ++x) out << *x << ' '; out << "}" << endl;}
MOD_DEFINE
const int N = 200000 + 5;
ll factorialNumInverse[N + 1];
ll naturalNumInverse[N + 1];
ll fact[N + 1];
void InverseofNumber(ll p)
{
naturalNumInverse[0] = naturalNumInverse[1] = 1;
for (int i = 2; i <= N; i++)
naturalNumInverse[i] = naturalNumInverse[p % i] * (p - p / i) % p;
}
void InverseofFactorial(ll p)
{
factorialNumInverse[0] = factorialNumInverse[1] = 1;
for (int i = 2; i <= N; i++)
factorialNumInverse[i] = (naturalNumInverse[i] * factorialNumInverse[i - 1]) % p;
}
void factorial(ll p)
{
fact[0] = 1;
for (int i = 1; i <= N; i++) {
fact[i] = (fact[i - 1] * i) % p;
}
}
ll Binomial(ll N, ll R, ll p)
{
if(R > N or R < 0 or N < 0) return 0;
ll ans = ((fact[N] * factorialNumInverse[R])% p * factorialNumInverse[N - R])% p;
return ans;
}
ll p = 998244353;
void slv(){
int n, m; cin >> n >> m;
cout << Binomial(2 * n + m - 1, m - 1, p) << endl; // stars and bars method
}
int32_t main(){
ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
// preprocess factorials
InverseofNumber(p);
InverseofFactorial(p);
factorial(p);
int T = 1;
cin >> T;
for(int t = 1; t <= T; t++){
slv();
}
return 0;
}
/*
*think brute force first.
*try proving the algorithm on pen n paper first.
*floating point precision errors ?
*implementation too lengthy ? logic might be incorrect.
*read the question again.
*/