586. Customer_Placing_the_Largest_Number_of_Orders.sql

      PROBLEM:
      
586. Customer Placing the Largest Number of Orders


SQL Schema
Table: Orders

+-----------------+----------+
| Column Name     | Type     |
+-----------------+----------+
| order_number    | int      |
| customer_number | int      |
+-----------------+----------+
order_number is the primary key for this table.
This table contains information about the order ID and the customer ID.
 

Write an SQL query to find the customer_number for the customer who has placed the largest number of orders.

The test cases are generated so that exactly one customer will have placed more orders than any other customer.

The query result format is in the following example.

 

Example 1:

Input: 
Orders table:
+--------------+-----------------+
| order_number | customer_number |
+--------------+-----------------+
| 1            | 1               |
| 2            | 2               |
| 3            | 3               |
| 4            | 3               |
+--------------+-----------------+
Output: 
+-----------------+
| customer_number |
+-----------------+
| 3               |
+-----------------+
Explanation: 
The customer with number 3 has two orders, which is greater than either customer 1 or 2 because each of them only has one order. 
So the result is customer_number 3.
 

Follow up: What if more than one customer has the largest number of orders, can you find all the customer_number in this case?




            
            SOLUTION:

#1.
SELECT
    customer_number
FROM
    orders
GROUP BY customer_number
ORDER BY COUNT(*) DESC
LIMIT 1
;


#2.
# Write your MySQL query statement below
SELECT customer_number 
FROM Orders
GROUP BY customer_number
ORDER BY COUNT(customer_number) DESC
LIMIT 1;