fix build

Author: CamDavidsonPilon

developer-guide/20-User interface/06-unit-api-reference.md

@@ -673,8 +673,6 @@ Get Running Jobs For Experiment endpoint.
 
 ## Get Job Settings
 
-{
-
 ### Endpoint
 `GET /unit_api/jobs/settings/job_name/{job_name}`
 

experiments/02-Secondary level education/low-vs-high-conc-media.md

@@ -40,14 +40,14 @@ Discuss with your students the following ideas:
 
 We created 1% YPD by adding 0.15 grams of YPD broth powder to 15 mL:
 
-$$\text \{w/v \%\}= \frac \{\text\{mass\}\}\{\text \{volume\}\}$$
+$$\text{w/v \%} = \frac{\text{mass}}{\text{volume}}$$
 
 $$
-\text \{mass\} = \{0.01\} \times \{15 \:\text \{mL\}\}
+\text{mass} = 0.01 \times 15 \:\text{mL}
 $$
 
 $$
-\text \{mass\} = 0.15 \:\text \{grams\}
+\text{mass} = 0.15 \:\text{grams}
 $$
 
 Using the same logic, 5% YPD was created by adding 0.75 grams to 15 mL.

experiments/02-Secondary level education/yeast-in-ethanol.md

@@ -44,17 +44,17 @@ We conducted an experiment using 4 Pioreactors and vials with ethanol concentrat
 The first concentration of 0% ethanol is easy &#151 we just add 1 mL of distilled water. For the rest, the following calculations were done to determine the volume of ethanol to add to each vial: 
 
 $$
-\frac\{[\text\{ethanol\}]\}\{\text\{media\thickspace volume + ethanol\thickspace volume\}\}=\text\{ethanol \%\}
+\frac{[\text{ethanol}]}{\text{media volume + ethanol volume}}=\text{ethanol \%}
 $$ 
 
 In our case, we have **15 mL** of YPD broth per vial, and want to add **1 mL** of diluted ethanol; we want to determine our final concentration of ethanol **in 1 mL** to get an overall 2% concentration in our complete, 16 mL of media. 
 
 For 2%: 
 $$
-\frac\{[\text\{ethanol\}]\}\{\text\{15 mL + 1 mL\}\}=\text\{2\%\}
+\frac{[\text{ethanol}]}{\text{15 mL + 1 mL}}=\text{2\%}
 $$
 $$
-[\text\{ethanol\}]=32\%
+[\text{ethanol}] = 32\%
 $$
 
 Now, we know we want our 1 mL of dilute ethanol concentration to equal 32%. Since we're starting with an initial concentration of 95%, we can apply the following dilution equation to figure out the concentration of 95% ethanol to use: 
@@ -67,10 +67,10 @@ Final concentration (C<sub>f</sub>)= 32%
 Now we substitute our variables into the equation C<sub>i</sub> V<sub>i</sub> = C<sub>f</sub> V<sub>f</sub>:
 
 $$
-V_i = \frac\{(32\%)(\text\{1 mL\})\}\{95\%\}
+V_i = \frac{(32\%)(\text{1 mL})}{95\%}
 $$ 
 $$
-V_i = \text\{0.34 mL\}
+V_i = \text{0.34 mL}
 $$
 
 So the composition to create 2% ethanol media is: 
@@ -95,16 +95,16 @@ Vial 4: 1 mL distilled water
 
 To calculate the resulting ethanol percentage: 
 $$
-\frac\{[\text\{ethanol\}]\}\{\text\{media\thickspace volume + ethanol\thickspace volume\}\}=\text\{ethanol \%\}
+\frac{[\text{ethanol}]}{\text{media volume + ethanol volume}}=\text{ethanol \%}
 $$ 
 
 Substitute the [ethanol] value for half of 95% (or 47.5%):
 
 $$
-\frac\{47.5\%\}\{\text\{15 mL + 1 mL\}\} = \text\{ethanol \%\}
+\frac{47.5\%}{\text{15 mL + 1 mL}} = \text{ethanol \%}
 $$
 $$
-\text\{ethanol \%\} \approx 3\%
+\text{ethanol \%} \approx 3\%
 $$
 
 This technique produces halving ethanol percentages of 0%, 1.5%, 3%, and 6% to be studied on a cluster of 4 Pioreactors. 
@@ -155,4 +155,4 @@ Plenty of yeast strains are available at your local breweries. You can do the sa
 
 Alba-Lois, L., & Segal-Kischinevzky, C. (2010). Yeast fermentation and the making of beer and wine. _Nature Education, 3_(9), 17.
 
-Gray, W. D. (1941). Studies on the alcohol tolerance of yeasts. _Journal of Bacteriology, 42_(5), 561-574. 
+Gray, W. D. (1941). Studies on the alcohol tolerance of yeasts. _Journal of Bacteriology, 42_(5), 561-574.