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| 1 | +/* |
| 2 | +File path (suggested): algorithms/sorting/RadixSort.java |
| 3 | +(If you want to use a package, uncomment the package line below and place the file accordingly) |
| 4 | +*/ |
| 5 | +// package algorithms.sorting; |
| 6 | + |
| 7 | +import java.util.Arrays; |
| 8 | + |
| 9 | +/** |
| 10 | + * Algorithm Name : Radix Sort |
| 11 | + * Programming Language: Java |
| 12 | + * Category: Sorting |
| 13 | + * Difficulty Level: Medium (Intermediate) |
| 14 | + * |
| 15 | + * Problem Statement: |
| 16 | + * Implement Radix Sort (LSD - least significant digit first) to sort an array |
| 17 | + * of non-negative integers. Use Counting Sort as a stable subroutine to sort |
| 18 | + * based on individual digit positions. |
| 19 | + * |
| 20 | + * Requirements: |
| 21 | + * - Input: array of non-negative integers |
| 22 | + * - Output: sorted array in ascending order |
| 23 | + * |
| 24 | + * Complexities: |
| 25 | + * - Time Complexity (Worst/Best/Average): O(d * (n + b)) |
| 26 | + * where d = number of digits in the maximum element, |
| 27 | + * n = number of elements, |
| 28 | + * b = base (10 for decimal) |
| 29 | + * - Space Complexity: O(n + b) |
| 30 | + * |
| 31 | + * Notes: |
| 32 | + * - This implementation assumes non-negative integers. To handle negative numbers, |
| 33 | + * separate negatives and positives, radix-sort their absolute values, then merge. |
| 34 | + */ |
| 35 | +public class RadixSort { |
| 36 | + |
| 37 | + /** |
| 38 | + * Utility to get maximum value in arr[] — used to determine how many digits. |
| 39 | + */ |
| 40 | + private static int getMax(int[] arr) { |
| 41 | + if (arr == null || arr.length == 0) return 0; |
| 42 | + int max = arr[0]; |
| 43 | + for (int v : arr) { |
| 44 | + if (v > max) max = v; |
| 45 | + } |
| 46 | + return max; |
| 47 | + } |
| 48 | + |
| 49 | + /** |
| 50 | + * A stable Counting Sort that sorts arr[] according to the digit represented by exp. |
| 51 | + * exp = 1 -> sort by 1's digit |
| 52 | + * exp = 10 -> sort by 10's digit |
| 53 | + * exp = 100 -> sort by 100's digit, etc. |
| 54 | + * |
| 55 | + * Complexity of this subroutine: O(n + b) where b = 10 (digits 0..9) |
| 56 | + */ |
| 57 | + private static void countingSortByDigit(int[] arr, int exp) { |
| 58 | + int n = arr.length; |
| 59 | + if (n == 0) return; |
| 60 | + |
| 61 | + int[] output = new int[n]; // output array to store sorted order by current digit |
| 62 | + int[] count = new int[10]; // count array for digits 0..9 (base 10) |
| 63 | + |
| 64 | + // 1) Count occurrences of each digit in the given exp place |
| 65 | + for (int i = 0; i < n; i++) { |
| 66 | + int digit = (arr[i] / exp) % 10; |
| 67 | + count[digit]++; |
| 68 | + } |
| 69 | + |
| 70 | + // 2) Convert count[] so that it contains actual positions (prefix sums) |
| 71 | + for (int i = 1; i < 10; i++) { |
| 72 | + count[i] += count[i - 1]; |
| 73 | + } |
| 74 | + |
| 75 | + // 3) Build the output array from right to left to maintain stability |
| 76 | + // (stable because elements with same digit appear in original relative order) |
| 77 | + for (int i = n - 1; i >= 0; i--) { |
| 78 | + int digit = (arr[i] / exp) % 10; |
| 79 | + int pos = count[digit] - 1; // index in output[] |
| 80 | + output[pos] = arr[i]; |
| 81 | + count[digit]--; // decrease count for this digit |
| 82 | + } |
| 83 | + |
| 84 | + // 4) Copy the output array back to arr[], so arr[] now contains numbers |
| 85 | + // sorted by current digit (exp) |
| 86 | + System.arraycopy(output, 0, arr, 0, n); |
| 87 | + } |
| 88 | + |
| 89 | + /** |
| 90 | + * Main Radix Sort routine — sorts the array using digit-by-digit counting sort. |
| 91 | + */ |
| 92 | + public static void radixSort(int[] arr) { |
| 93 | + if (arr == null || arr.length <= 1) return; // already sorted or nothing to do |
| 94 | + |
| 95 | + // Find the maximum number to know the number of digits |
| 96 | + int max = getMax(arr); |
| 97 | + |
| 98 | + // Do counting sort for every digit. Note that instead of passing the digit number, |
| 99 | + // exp is passed. exp is 10^i where i is current digit number (0 -> LSD). |
| 100 | + for (int exp = 1; max / exp > 0; exp *= 10) { |
| 101 | + countingSortByDigit(arr, exp); |
| 102 | + } |
| 103 | + } |
| 104 | + |
| 105 | + /** Utility to print array in a readable form. */ |
| 106 | + private static void printArray(String label, int[] arr) { |
| 107 | + System.out.println(label + Arrays.toString(arr)); |
| 108 | + } |
| 109 | + |
| 110 | + /** Sample test cases covering: small arrays, repeated numbers, single-element array */ |
| 111 | + public static void main(String[] args) { |
| 112 | + // Test case 1: Small array (classic example) |
| 113 | + int[] arr1 = {170, 45, 75, 90, 802, 24, 2, 66}; |
| 114 | + printArray("Original arr1: ", arr1); |
| 115 | + radixSort(arr1); |
| 116 | + printArray("Sorted arr1: ", arr1); |
| 117 | + System.out.println(); |
| 118 | + |
| 119 | + // Test case 2: Array with repeated numbers |
| 120 | + int[] arr2 = {5, 3, 5, 2, 8, 5, 3}; |
| 121 | + printArray("Original arr2: ", arr2); |
| 122 | + radixSort(arr2); |
| 123 | + printArray("Sorted arr2: ", arr2); |
| 124 | + System.out.println(); |
| 125 | + |
| 126 | + // Test case 3: Single-element array |
| 127 | + int[] arr3 = {42}; |
| 128 | + printArray("Original arr3: ", arr3); |
| 129 | + radixSort(arr3); |
| 130 | + printArray("Sorted arr3: ", arr3); |
| 131 | + System.out.println(); |
| 132 | + |
| 133 | + // Optional: Empty array test |
| 134 | + int[] arr4 = {}; |
| 135 | + printArray("Original arr4: ", arr4); |
| 136 | + radixSort(arr4); |
| 137 | + printArray("Sorted arr4: ", arr4); |
| 138 | + } |
| 139 | +} |
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