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23 changes: 22 additions & 1 deletion 06/tasks/task_32_decode_string.py
Original file line number Diff line number Diff line change
Expand Up @@ -5,4 +5,25 @@ def decode_string(s: str) -> str:
Dekóduje zakódovaný řetězec ve formátu k[encoded_string],
např. "3[a]2[bc]" → "aaabcbc".
"""

while '[' in s:
pos_left_bracket = s.index('[')
pos_right_bracket = s.index(']')
# check for nested brackets
if '[' in s[pos_left_bracket + 1:]:
pos_left_bracket2 = s.index('[', pos_left_bracket + 1)
else:
pos_left_bracket2 = len(s) + 1
# no nested brackets
if pos_right_bracket < pos_left_bracket2:
pos_num = pos_left_bracket - 1
num = ''
while s[pos_num].isdigit():
num = s[pos_num] + num
pos_num += -1
s = s[:pos_left_bracket - len(num)] + int(
num) * s[pos_left_bracket + 1:pos_right_bracket] + s[pos_right_bracket + 1:]
Comment on lines +23 to +24

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Ne vzdy to autopep8 zalomi vhodne. Nekdy tomu musime sami pomoct.

# nested brackets
else:
s = s[:pos_left_bracket + 1] + \
decode_string(s[pos_left_bracket + 1:])
return s