Hey guys, I need to open the app after I click on the notification. Now it doesn't do anything.
My xml code
<manifest xmlns:android="http://schemas.android.com/apk/res/android">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.FOREGROUND_SERVICE" />
<uses-permission android:name="android.permission.WAKE_LOCK" />
<application
android:name=".MainApplication"
android:label="@string/app_name"
android:icon="@mipmap/ic_launcher"
android:roundIcon="@mipmap/ic_launcher_round"
android:allowBackup="false"
android:theme="@style/AppTheme">
<service android:name="com.asterinet.react.bgactions.RNBackgroundActionsTask" />
<activity
android:name=".MainActivity"
android:label="@string/app_name"
android:configChanges="keyboard|keyboardHidden|orientation|screenLayout|screenSize|smallestScreenSize|uiMode"
android:launchMode="singleTask"
android:windowSoftInputMode="adjustResize"
android:exported="true">
<intent-filter android:label="filter_react_native">
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="yourSchemeHere" />
</intent-filter>
</activity>
</application>
</manifest>my JSX code
/**
* Sample React Native App
* https://github.com/facebook/react-native
*
* @format
*/
import React from 'react';
import { StyleSheet, Text, View, Button } from 'react-native';
import BackgroundService from 'react-native-background-actions';
const sleep = (time:number) => new Promise<void>((resolve) => setTimeout(() => resolve(), time));
const veryIntensiveTask = async (taskDataArguments:any) => {
console.log("in intensive task");
const { delay } = taskDataArguments;
await new Promise( async (resolve) => {
for (let i = 0; BackgroundService.isRunning(); i++) {
const date = `${new Date().getHours()}:${new Date().getMinutes()}:${new Date().getSeconds()}`;
console.log(`${i} => ${date}`);
await sleep(delay);
}
});
};
const options = {
taskName: 'Example',
taskTitle: 'ExampleTask title',
taskDesc: 'ExampleTask description',
taskIcon: {
name: 'ic_launcher',
type: 'mipmap',
},
color: '#ff00ff',
linkingURI: 'yourSchemeHere://chat/jane',
parameters: {
delay: 1000,
},
};
export default function Background(){
const startBackgoundJob=async ()=>{
await BackgroundService.start(veryIntensiveTask, options);
console.log("background service started");
};
const updateBackgroundJob=async ()=>{
await BackgroundService.updateNotification({taskDesc: 'New ExampleTask description'});
console.log("background service updated");
};
const stopBackgroundJob=async ()=>{
await BackgroundService.stop();
console.log("background service stopped");
};
return(
<View style={{flex:1,display:"flex",justifyContent:"center",alignItems:"center"}}>
<Button title="start background job" onPress={startBackgoundJob}/>
<Button title="update background job" onPress={updateBackgroundJob}/>
<Button title="stop background job" onPress={stopBackgroundJob}/>
</View>
)
}Please let me know if you know how i can do it.
Hey guys, I need to open the app after I click on the notification. Now it doesn't do anything.
My xml code
my JSX code
Please let me know if you know how i can do it.