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P0155_MinStack.java
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100 lines (87 loc) · 2.92 KB
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package yyl.leetcode.p01;
import yyl.leetcode.util.Assert;
/**
* <h3>最小栈</h3><br>
* 设计一个支持 push ,pop ,top 操作,并能在常数时间内检索到最小元素的栈。<br>
* ├ push(x) —— 将元素 x 推入栈中。<br>
* ├ pop() —— 删除栈顶的元素。<br>
* ├ top() —— 获取栈顶元素。<br>
* └ getMin() —— 检索栈中的最小元素。<br>
*
* <pre>
* 示例:
* 输入:
* ["MinStack","push","push","push","getMin","pop","top","getMin"]
* [[],[-2],[0],[-3],[],[],[],[]]
* 输出:
* [null,null,null,null,-3,null,0,-2]
* 解释:
* MinStack minStack = new MinStack();
* minStack.push(-2);
* minStack.push(0);
* minStack.push(-3);
* minStack.getMin(); --> 返回 -3.
* minStack.pop();
* minStack.top(); --> 返回 0.
* minStack.getMin(); --> 返回 -2.
* </pre>
*
* 提示: pop、top 和 getMin 操作总是在 非空栈 上调用。<br>
*/
public class P0155_MinStack {
public static void main(String[] args) {
MinStack stack = new MinStack();
stack.push(-2);
stack.push(0);
stack.push(-3);
Assert.assertEquals(-3, stack.getMin());
stack.pop();
Assert.assertEquals(0, stack.top());
Assert.assertEquals(-2, stack.getMin());
}
// 单链表
// 栈结构的特性:“先进后出”
// 自定义栈,使用链表结构模拟栈结,链表每个节点存储当前对应的最小值。
// ├ 当一个元素要入栈时,取当前栈顶存储的最小值,与当前元素比较得出最小值;
// └ 当一个元素要出栈时,将头指向下一个元素;
// 时间复杂度:O(1)。因为栈的插入、删除与读取操作都是 O(1)。
// 空间复杂度:O(n),其中 n 为总操作数。最坏情况下,会连续插入 n 个元素,此时栈占用的空间为 O(n)。
static class MinStack {
private Node head;
/** initialize your data structure here. */
public MinStack() {
}
public void push(int x) {
if (head == null) {
head = new Node(x, x, null);
} else {
head = new Node(x, Math.min(head.min, x), head);
}
}
public void pop() {
head = head.next;
}
public int top() {
return head.value;
}
public int getMin() {
return head.min;
}
class Node {
private int value;
private int min;
private Node next;
private Node(int value, int min, Node next) {
this.value = value;
this.min = min;
this.next = next;
}
}
}
// Your MinStack object will be instantiated and called as such:
// MinStack obj = new MinStack();
// obj.push(x);
// obj.pop();
// int param_3 = obj.top();
// int param_4 = obj.getMin();
}