Refactor isSubsequence method for clarity

Author: RispaJoseph

0392-is-subsequence/solution.py

@@ -1,11 +1,10 @@
 class Solution:
     def isSubsequence(self, s: str, t: str) -> bool:
-        len_of_str = len(s)
         i = 0
 
-        for j in range(len(t)):
-            if i < len_of_str and t[j] == s[i]:
+        for char in t:
+            if i < len(s) and s[i] == char:
                 i += 1
-
-        return i == len_of_str
+        return i == len(s)
+