Skip to content

Commit 0e3715a

Browse files
committed
Sh(X,Ab) is not split abelian
1 parent 386e82b commit 0e3715a

File tree

2 files changed

+6
-5
lines changed

2 files changed

+6
-5
lines changed

database/data/001_categories/200_comments.sql

Lines changed: 1 addition & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -38,7 +38,7 @@ VALUES
3838
),
3939
(
4040
'Sh(X,Ab)',
41-
'It is likely that neither of the currently remaining unknown properties (finitary algebraic, locally ℵ₁-presentable, split abelian, etc.) are satisfied for a <i>generic</i> space $X$, but we need to make this precise by adding additional requirements to $X$. Maybe we need to create separate entries for specific spaces $X$.'
41+
'It is likely that neither of the currently remaining unknown properties (finitary algebraic, locally ℵ₁-presentable, etc.) are satisfied for a <i>generic</i> space $X$, but we need to make this precise by adding additional requirements to $X$. Maybe we need to create separate entries for specific spaces $X$.'
4242
),
4343
(
4444
'M-Set',

database/data/004_property-assignments/Sh(X,Ab).sql

Lines changed: 5 additions & 4 deletions
Original file line numberDiff line numberDiff line change
@@ -19,13 +19,14 @@ VALUES
1919
),
2020
(
2121
'Sh(X,Ab)',
22-
'trivial',
22+
'skeletal',
2323
FALSE,
24-
'Consider constant sheaves for non-isomorphic abelian groups.'
24+
'Consider constant sheaves for isomorphic but non-equal abelian groups.'
2525
),
2626
(
2727
'Sh(X,Ab)',
28-
'skeletal',
28+
'split abelian',
2929
FALSE,
30-
'Consider constant sheaves for isomorphic but non-equal abelian groups.'
30+
'Choose a point $x \in X$. The functor $x_* : \mathbf{Ab} \to \mathrm{Sh}(X,\mathbf{Ab})$ (skyscraper sheaf) is exact, and its left adjoint $x^* : \mathrm{Sh}(X,\mathbf{Ab}) \to \mathbf{Ab}$ (stalk) satisfies $x^* x_* \cong \mathrm{id}_{\mathbf{Ab}}$. Now, since $\mathbf{Ab}$ is not split abelian (see <a href="/category/Ab">here</a>), there is a short exact sequence of abelian groups $0 \to A \to B \to C \to 0$ that does not split. Then $0 \to x_* A \to x_* B \to x_* C \to 0$ is also exact, but it does not split: Otherwise it would also be split after applying $x^*$, which however gives the original sequence in $\mathbf{Ab}$.'
3131
);
32+

0 commit comments

Comments
 (0)