I claim that epimorphisms in Alg(R) are simply morphisms of R-algebras which happen to be epimorphisms of commutative rings.
Let f : A -> B be a morphism of R-algebras. It is clear that if f is an epimorphism in CRing, then it is an epimorphism in Alg(R). Conversely, suppose f is an epimorphism in Alg(R).
Now we notice that the two natural maps B -> B \otimes_A B are R-algebra homomorphisms.
Since the two composites A -> B -> B \otimes_A B are equal and f is an epimorphism, we conclude that the two natural maps B -> B \otimes_A B are equal.
This implies that f is an epimorphism of commutative rings (see https://stacks.math.columbia.edu/tag/04VN).
This issue has been created by Ben Spitz via the submission form on https://catdat.app/category/Alg(R)
I claim that epimorphisms in Alg(R) are simply morphisms of R-algebras which happen to be epimorphisms of commutative rings.
Let f : A -> B be a morphism of R-algebras. It is clear that if f is an epimorphism in CRing, then it is an epimorphism in Alg(R). Conversely, suppose f is an epimorphism in Alg(R).
Now we notice that the two natural maps B -> B \otimes_A B are R-algebra homomorphisms.
Since the two composites A -> B -> B \otimes_A B are equal and f is an epimorphism, we conclude that the two natural maps B -> B \otimes_A B are equal.
This implies that f is an epimorphism of commutative rings (see https://stacks.math.columbia.edu/tag/04VN).
This issue has been created by Ben Spitz via the submission form on https://catdat.app/category/Alg(R)