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一致性hash中,相同入参无法路由到同一个服务 #63

@Tbthr

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@Tbthr

return selector.select(rpcServiceName + Arrays.stream(rpcRequest.getParameters()));

Arrays.stream() 每次调用都会返回一个新对象,即使入参相同。如下图所示:
image

客户端调用,如下图所示:
image

是否可以直接将参数按顺序拼接呢,个人的一些思考,还望指教

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