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<li>A <term>rotation</term> is given by <m>\vec{v} \mapsto \left[\begin{array}{c} \cos(\theta)x - \sin(\theta)y\\ \cos(\theta)y + \sin(\theta)x\end{array}\right].</m></li>
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<li>A <term>reflection</term> of <m>\vec{v}</m> over a line <m>l</m> can be found by first finding a vector <m>\vec{l} = \left[\begin{array}{c} l_x\\l_y\end{array}\right]</m> along <m>l</m>, then <m>\vec{v} \mapsto 2\frac{\vec{l}\cdot\vec{v}}{\vec{l}\cdot\vec{l}}\vec{l} - \vec{v}.</m></li>
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<li>A <term>reflection</term> of <m>\vec{v}</m> over a line <m>l</m> can be found by first finding a vector <m>\vec{l} = \left[\begin{array}{c} l_x\\l_y\end{array}\right]</m> along <m>l</m>, then <m>\vec{v} \mapsto 2 \left(\dfrac{\vec{l}\cdot\vec{v}}{\vec{l}\cdot\vec{l}}\right) \vec{l} - \vec{v}.</m></li>
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Represent each of the following transformations with respect to the standard basis in <m>\mathbb{R}^2</m>.
Copy file name to clipboardExpand all lines: source/linear-algebra/source/03-AT/04.ptx
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</li>
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<li>
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<p>
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The system of equations given by <m>[A|\vec{0}]</m> has a unique solution.
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The system of equations given by <m>[A\,|\,\vec{0}]</m> has a unique solution.
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</p>
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</li>
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</ol>
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</li>
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<li>
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<p>
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The system of equations given by <m>[A|\vec{b}]</m> is always consistent.
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The system of equations given by <m>[A\,|\,\vec{b}]</m> is always consistent.
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</p>
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</li>
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<exploration><statement>
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<p>Start with an <m>n</m>-dimensional vector space <m>V</m>. We can define the <term>dual</term> of <m>V</m>, denoted <m>V^*</m>, by
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<me>V^* = \{h:V \rightarrow \mathbb{R}: h \mbox{ is linear}\}.</me>
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Prove that <m>V</m> is isomorphic to<m>V^*</m>. Here are some things to think about as you work through this.
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Prove that <m>V</m> is isomorphic to<m>V^*</m>. Here are some things to think about as you work through this.
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<ul>
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<li>Start by assuming you have a basis for <m>V</m>. How many basis vectors should you have?</li>
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<li>For each basis vector in <m>V</m>, define a function that returns 1 if it's given that basis vector, and returns 0 if it's given any other basis vector. For example, if <m>\vec{b_i}</m> and <m>\vec{b_j}</m> are each members of the basis for <m>V</m>, and you'll need a function <m>f_i:V \rightarrow \{0,1\}</m>, where <m>f_i(b_i) = 1</m> and <m>f_i(b_j)= 0</m> for all <m> j \neq i</m>.</li>
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