added 3 DSA questions in python

data_structures/arrays/fruit_into_baskets.py

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+"""
+Question:
+Given an array fruits representing types of fruit, pick a contiguous subarray containing at most 2 different types of fruit.
+Return the maximum number of fruits you can collect.
+
+Example:
+Input: fruits = [1,2,1,2,3]
+Output: 4
+Explanation:
+Pick subarray [1,2,1,2] -> contains 2 types and length 4
+"""
+
+from typing import List
+from collections import defaultdict
+
+class FruitIntoBaskets:
+    def total_fruit(self, fruits: List[int]) -> int:
+        count = defaultdict(int)  # Stores count of each fruit type
+        left = 0  # Left pointer of sliding window
+        max_fruit = 0  # Tracks max number of fruits collected
+
+        for right, fruit in enumerate(fruits):
+            count[fruit] += 1  # Include current fruit
+
+            # Shrink window if more than 2 types
+            while len(count) > 2:
+                count[fruits[left]] -= 1
+                if count[fruits[left]] == 0:
+                    del count[fruits[left]]
+                left += 1
+
+            max_fruit = max(max_fruit, right - left + 1)
+
+        return max_fruit
+
+# Example dry run
+if __name__ == "__main__":
+    fruits = [1,2,1,2,3]
+    solver = FruitIntoBaskets()
+    print("Maximum Fruits Collected:", solver.total_fruit(fruits))

data_structures/arrays/longest_ones_after_replacement.py

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+"""
+Question:
+Given a binary array nums and an integer k, find the length of the longest subarray containing 1s after flipping at most k zeros.
+
+Example:
+Input: nums = [1,0,1,1,0,1], k = 1
+Output: 4
+Explanation:
+Flip the first 0 at index 1 -> subarray [1,1,1,1] has length 4
+"""
+
+from typing import List
+
+class LongestOnesAfterReplacement:
+    def longest_ones(self, nums: List[int], k: int) -> int:
+        left = 0  # Left pointer of sliding window
+        max_len = 0  # Tracks maximum window length
+        zeros_count = 0  # Count of zeros in current window
+
+        for right in range(len(nums)):
+            if nums[right] == 0:
+                zeros_count += 1
+
+            # Shrink window if zeros exceed k
+            while zeros_count > k:
+                if nums[left] == 0:
+                    zeros_count -= 1
+                left += 1
+
+            max_len = max(max_len, right - left + 1)
+
+        return max_len
+
+# Example dry run
+if __name__ == "__main__":
+    nums = [1,0,1,1,0,1]
+    k = 1
+    solver = LongestOnesAfterReplacement()
+    print("Longest Ones After Replacement:", solver.longest_ones(nums, k))

data_structures/arrays/sliding_window_maximum.py

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+"""
+Question:
+Given an integer array nums and an integer k, return the maximum value in each sliding window of size k.
+
+Example:
+Input: nums = [1,3,-1,-3,5,3,6,7], k = 3
+Output: [3,3,5,5,6,7]
+Explanation:
+Window positions and max values:
+[1,3,-1] -> max = 3
+[3,-1,-3] -> max = 3
+[-1,-3,5] -> max = 5
+[-3,5,3] -> max = 5
+[5,3,6] -> max = 6
+[3,6,7] -> max = 7
+"""
+
+from collections import deque
+from typing import List
+
+class SlidingWindowMaximum:
+    def max_sliding_window(self, nums: List[int], k: int) -> List[int]:
+        if not nums:
+            return []
+
+        result = []  # Stores max of each window
+        window = deque()  # Stores indices of elements in current window
+
+        for i, num in enumerate(nums):
+            # Remove indices of elements outside current window
+            while window and window[0] <= i - k:
+                window.popleft()
+
+            # Remove indices of elements smaller than current num
+            while window and nums[window[-1]] < num:
+                window.pop()
+
+            window.append(i)
+
+            # Add the max for this window to result
+            if i >= k - 1:
+                result.append(nums[window[0]])
+
+        return result
+
+# Example dry run
+if __name__ == "__main__":
+    nums = [1,3,-1,-3,5,3,6,7]
+    k = 3
+    solver = SlidingWindowMaximum()
+    print("Sliding Window Maximum:", solver.max_sliding_window(nums, k))