Fix some spelling errors

Author: cbm755

.codespell-ignorewords

@@ -7,5 +7,7 @@
 # without any warranty.
 
 # words that codespell should not complain about
+
 co-ordinates
 co-ordinate
+ans

Chapters/chapter2.tex

@@ -1853,7 +1853,7 @@ \subsection{Problems}
 \begin{problem}
 \label{op1_32}
 Find the equation for the line through $[2,-1,-1]$ and parallel to each of the
-two planes $x_1+x_2=0$ and $x_1-x_2+2x_3=0$. Express the equation fo the line
+two planes $x_1+x_2=0$ and $x_1-x_2+2x_3=0$. Express the equation of the line
 in both parametric and equation form.
 \end{problem}
 

Chapters/chapter3.tex

@@ -1124,16 +1124,16 @@ \subsection{Connection of solutions to homogeneous and inhomogeneous systems.}
 \]
 To see the implications of this let us  suppose that $\xx=\qq$ is any particular
 solution to a (non-homogeneous) system of equations. Then if $\yy$ is any other
-solution $\yy-\xx=\zz$ is a solution of the corresponding homogenous system.
+solution $\yy-\xx=\zz$ is a solution of the corresponding homogeneous system.
 So $\yy=\qq+\zz$. In other words any solution can be written as $\qq +$ some
-solution of the corresponding homogenous system. Going the other way, if
-$\zz$ is any solution of the corresponding homogenous system, then $\qq+\zz$
+solution of the corresponding homogeneous system. Going the other way, if
+$\zz$ is any solution of the corresponding homogeneous system, then $\qq+\zz$
 solves the original system. This can be seen by plugging $\qq+\zz$ into the
 equation. So the structure of the set of solutions is
 \[
 \xx = \qq + (\mbox{{\ \bf solution to homogeneous system}})
 \]
-As you run through all solutions to the homogenous system on the right,
+As you run through all solutions to the homogeneous system on the right,
 $\xx$ runs through all solutions of the original system. Notice that it doesn't
 matter which $\qq$ you choose as the starting point. This is completely analogous
 to the parametric form for a line, where the base point can be any
@@ -2720,7 +2720,7 @@ \section{Solutions to Chapter Problems}
 \end{eqnarray*}
 Hence, we have that $\qq = (-3, -6, 1, 7)$.
 
-Now, to find $\aa$, the homogenous row echelon form is
+Now, to find $\aa$, the homogeneous row echelon form is
 $$
 \left[\begin{array}{cccc|c}
      1 & 2 & 2 & 2 & 0 \\