Fix isEventTypeLoggingEnabled bug where empty string matches eventTypeId 0 (calcom#24804)

When BOOKING_LOGGING_EVENT_IDS is set to an empty string, the current
implementation splits it into [''] and Number('') returns 0, causing
any event type with ID 0 to incorrectly trigger debug logging.

This fix:
- Filters out empty/invalid event IDs (NaN, <=0)
- Filters out empty usernames
- Only matches valid, positive event type IDs

Co-authored-by: Devin AI <158243242+devin-ai-integration[bot]@users.noreply.github.com>

Author: emrysal

packages/features/bookings/lib/isEventTypeLoggingEnabled.ts

@@ -9,19 +9,25 @@ export function isEventTypeLoggingEnabled({
     usernameOrTeamName instanceof Array ? usernameOrTeamName : [usernameOrTeamName];
   // eslint-disable-next-line turbo/no-undeclared-env-vars
   const bookingLoggingEventIds = process.env.BOOKING_LOGGING_EVENT_IDS || "";
-  const isEnabled = bookingLoggingEventIds.split(",").some((id) => {
-    if (Number(id.trim()) === eventTypeId) {
-      return true;
-    }
-  });
+  const validEventIds = bookingLoggingEventIds
+    .split(",")
+    .map((id) => Number(id.trim()))
+    .filter((id) => !isNaN(id) && id > 0);
+
+  const isEnabled = eventTypeId && validEventIds.includes(eventTypeId);
 
   if (isEnabled) {
     return true;
   }
 
   // eslint-disable-next-line turbo/no-undeclared-env-vars
   const bookingLoggingUsername = process.env.BOOKING_LOGGING_USER_OR_TEAM_NAME || "";
-  return bookingLoggingUsername.split(",").some((u) => {
-    return usernameOrTeamnamesList.some((foundUsername) => foundUsername === u.trim());
+  const validUsernames = bookingLoggingUsername
+    .split(",")
+    .map((u) => u.trim())
+    .filter((u) => u.length > 0);
+
+  return validUsernames.some((username) => {
+    return usernameOrTeamnamesList.some((foundUsername) => foundUsername === username);
   });
 }