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LeetCode #19: Remove Nth Node From End of List #139

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Merged
WazedKhan merged 1 commit into from
Jun 28, 2026
+30 −0
Merged

LeetCode #19: Remove Nth Node From End of List #139

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30 changes: 30 additions & 0 deletions LeetCode/medium/remove_nth_from_end_19.py
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Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
from typing import Optional


class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
Comment on lines +5 to +7

@coderabbitai coderabbitai Bot Jun 28, 2026

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📐 Maintainability & Code Quality | 🟡 Minor | ⚡ Quick win

Rename next to avoid builtin shadowing.
This keeps lint noise down and avoids reusing a builtin name.

🧰 Tools
🪛 Ruff (0.15.18)

[error] 5-5: Function argument next is shadowing a Python builtin

(A002)

🤖 Prompt for AI Agents 
Verify each finding against current code. Fix only still-valid issues, skip the
rest with a brief reason, keep changes minimal, and validate.

In `@LeetCode/medium/remove_nth_from_end_19.py` around lines 5 - 7, Rename the
ListNode initializer parameter in the ListNode class from next to a non-builtin
name and update the assignment accordingly; make the change in the __init__
method so the constructor signature and any internal references no longer shadow
the builtin name.



class Solution:
def length(self, head: ListNode) -> int:
count = 0
current = head
while current:
count += 1
current = current.next
return count

def removeNthFromEnd(self, head: Optional[ListNode], n: int) -> Optional[ListNode]:
n_len = self.length(head=head)
position = n_len - n
dummy = ListNode(0)
dummy.next = head
prev = dummy

for _ in range(position):
prev = prev.next
prev.next = prev.next.next

return dummy.next
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