LeetCode #143: Reorder List#140
Conversation
|
Warning Review limit reached
Next review available in: 58 minutes Enable usage-based reviews in Billing to review now. Otherwise, wait until the next included review is available. How can I continue?After more reviews become available, a review can be triggered using the To avoid repeated limits, reduce automatic review volume by pausing incremental auto-reviews earlier, using label-based review opt-in, excluding WIP or generated PR titles, or requesting reviews manually when the PR is ready. If your team needs uninterrupted high-volume reviews, an organization admin can enable usage-based reviews. How do review limits work?CodeRabbit enforces per-developer PR review limits for each organization. Most developers receive the normal plan review availability. For paid Pro and Pro+ PR reviews, CodeRabbit uses adaptive limits for sustained high-volume activity. When a developer's recent PR review activity reaches the 95th percentile or higher among CodeRabbit users, additional reviews become available more gradually as earlier reviews age out of the rolling window. Please refer docs for additional details. Review details⚙️ Run configurationConfiguration used: defaults Review profile: CHILL Plan: Pro Run ID: 📒 Files selected for processing (1)
📝 WalkthroughWalkthroughA new LeetCode solution module is added for problem 143 (Reorder List), defining a ChangesReorder List Implementation
Estimated code review effort: 1 (Trivial) | ~5 minutes Estimated code review effort1 (Trivial) | ~5 minutes Suggested labels: enhancement, leetcode Suggested reviewers: WazedKhan 🐰 A list once split, now woven tight, 🚥 Pre-merge checks | ✅ 5✅ Passed checks (5 passed)
✨ Finishing Touches🧪 Generate unit tests (beta)
Thanks for using CodeRabbit! It's free for OSS, and your support helps us grow. If you like it, consider giving us a shout-out. Comment |
![coderabbitai[bot]](https://avatars.githubusercontent.com/in/347564?s=60&v=4){kind=small}
There was a problem hiding this comment.
Actionable comments posted: 1
🤖 Prompt for all review comments with AI agents
Verify each finding against current code. Fix only still-valid issues, skip the
rest with a brief reason, keep changes minimal, and validate.
Inline comments:
In `@LeetCode/medium/reorder_list_143.py`:
- Around line 19-26: The reorderList method currently assumes head is non-null,
which causes a crash when called with an empty list. Update reorderList in the
Solution class to handle the None case up front before using slow.next, so the
fast/slow split logic only runs when head exists. Keep the existing midpoint
logic and next-pointer splitting intact after the early return.
🪄 Autofix (Beta)
Fix all unresolved CodeRabbit comments on this PR:
- Push a commit to this branch (recommended)
- Create a new PR with the fixes
ℹ️ Review info
⚙️ Run configuration
Configuration used: defaults
Review profile: CHILL
Plan: Pro
Run ID: 001a0d6e-970b-455c-8f74-d43ebdb19e5c
📒 Files selected for processing (1)
LeetCode/medium/reorder_list_143.py
| def reorderList(self, head: Optional[ListNode]) -> None: | ||
| slow, fast = head, head | ||
|
|
||
| while fast and fast.next: | ||
| slow = slow.next | ||
| fast = fast.next.next | ||
| half = slow.next | ||
| slow.next = None |
There was a problem hiding this comment.
🩺 Stability & Availability | 🟠 Major | ⚡ Quick win
Crashes on empty list input.
If head is None, slow and fast both start as None; the while fast and fast.next loop is skipped, leaving slow as None. Line 25 then does slow.next, raising AttributeError: 'NoneType' object has no attribute 'next'.
🐛 Proposed fix
def reorderList(self, head: Optional[ListNode]) -> None:
+ if not head or not head.next:
+ return
slow, fast = head, head📝 Committable suggestion
‼️ IMPORTANT
Carefully review the code before committing. Ensure that it accurately replaces the highlighted code, contains no missing lines, and has no issues with indentation. Thoroughly test & benchmark the code to ensure it meets the requirements.
| def reorderList(self, head: Optional[ListNode]) -> None: | |
| slow, fast = head, head | |
| while fast and fast.next: | |
| slow = slow.next | |
| fast = fast.next.next | |
| half = slow.next | |
| slow.next = None | |
| def reorderList(self, head: Optional[ListNode]) -> None: | |
| if not head or not head.next: | |
| return | |
| slow, fast = head, head | |
| while fast and fast.next: | |
| slow = slow.next | |
| fast = fast.next.next | |
| half = slow.next | |
| slow.next = None |
🤖 Prompt for AI Agents
Verify each finding against current code. Fix only still-valid issues, skip the
rest with a brief reason, keep changes minimal, and validate.
In `@LeetCode/medium/reorder_list_143.py` around lines 19 - 26, The reorderList
method currently assumes head is non-null, which causes a crash when called with
an empty list. Update reorderList in the Solution class to handle the None case
up front before using slow.next, so the fast/slow split logic only runs when
head exists. Keep the existing midpoint logic and next-pointer splitting intact
after the early return.
1 participant
Summary by CodeRabbit