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1008 lines (739 loc) · 25.7 KB
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//-------------------------------------------
//-------------------------------------------
function merge( array1, array2 ) {
let merged = [];
while ( array1.length || array2.length ) {
let ele1 = array1.length ? array1[ 0 ] : Infinity;
let ele2 = array2.length ? array2[ 0 ] : Infinity;
let next;
if ( ele1 < ele2 ) {
next = array1.shift();
} else {
next = array2.shift();
}
merged.push( next );
}
return merged;
}
//---
-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
//-------------------------------------------
// commented
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
merge( [ 10, 13, 15, 25 ], [] ); // => [10, 13, 15, 25]
//-------------------------------------------
//-------------------------------------------
function mergeSort( array ) {
if ( array.length <= 1 ) {
return array;
}
//...some code here.
}
//If our base case pretains to an array of a very small size, then the design of our recursive case should make progress toward hitting this base scenario. In other words, we should recursively call `mergeSort` on smaller and smaller arrays. A logical way to do this is to take the input array and split it into left and right halves.
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
function mergeSort( array ) {
if ( array.length <= 1 ) {
return array;
}
let midIdx = Math.floor( array.length / 2 );
let leftHalf = array.slice( 0, midIdx );
let rightHalf = array.slice( midIdx );
let sortedLeft = mergeSort( leftHalf );
let sortedRight = mergeSort( rightHalf );
return merge( sortedLeft, sortedRight );
}
//Wow. that's it. Notice how light the implementation of `mergeSort` is. Much of the heavy lifting (the actually comparisons) is done by the `merge` helper.
//-------------------------------------------
//-------------------------------------------
function merge( array1, array2 ) {
let merged = [];
while ( array1.length || array2.length ) {
let ele1 = array1.length ? array1[ 0 ] : Infinity;
let ele2 = array2.length ? array2[ 0 ] : Infinity;
let next;
if ( ele1 < ele2 ) {
next = array1.shift();
} else {
next = array2.shift();
}
merged.push( next );
}
return merged;
}
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
function partition( array, pivot ) {
let left = [];
let right = [];
array.forEach( ( el ) => {
if ( el < pivot ) {
left.push( el );
} else {
right.push( el );
}
} );
return [ left, right ];
}
//-------------------------------------------
//-------------------------------------------
function partition( array, pivot ) {
let left = array.filter( ( el ) => el < pivot );
let right = array.filter( ( el ) => el >= pivot );
return [ left, right ];
}
//-------------------------------------------
//-------------------------------------------
function quickSort( array ) {
if ( array.length <= 1 ) {
return array;
}
}
//-------------------------------------------
//-------------------------------------------
function quickSort( array ) {
if ( array.length <= 1 ) {
return array;
}
//-------------------------------------------
//-------------------------------------------
let pivot = array.shift();
let left = array.filter( ( el ) => el < pivot );
let right = array.filter( ( el ) => el >= pivot );
//...some code here
//-------------------------------------------
//-------------------------------------------
function quickSort( array ) {
if ( array.length <= 1 ) {
return array;
}
let pivot = array.shift();
let left = array.filter( el => el < pivot );
let right = array.filter( el => el >= pivot );
let leftSorted = quickSort( left );
let rightSorted = quickSort( right );
//...some code here
//-------------------------------------------
//-------------------------------------------
function quickSort( array ) {
if ( array.length <= 1 ) {
return array;
}
let pivot = array.shift();
let left = array.filter( ( el ) => el < pivot );
let right = array.filter( ( el ) => el >= pivot );
let leftSorted = quickSort( left );
let rightSorted = quickSort( right );
return leftSorted.concat( [ pivot ] ).concat( rightSorted );
}
//-------------------------------------------
//-------------------------------------------
let one = [ "a", "b" ];
let two = [ "d", "e", "f" ];
let newArr = [ ...one, "c", ...two ];
newArr; // => [ 'a', 'b', 'c', 'd', 'e', 'f' ]
//-------------------------------------------
//-------------------------------------------
function quickSort( array ) {
if ( array.length <= 1 ) {
return array;
}
let pivot = array.shift();
let left = array.filter( ( el ) => el < pivot );
let right = array.filter( ( el ) => el >= pivot );
let leftSorted = quickSort( left );
let rightSorted = quickSort( right );
return [ ...leftSorted, pivot, ...rightSorted ];
}
//-------------------------------------------
//-------------------------------------------
function quickSort( array ) {
if ( array.length <= 1 ) {
return array;
}
let pivot = array.shift();
let left = array.filter( ( el ) => el < pivot );
let right = array.filter( ( el ) => el >= pivot );
let leftSorted = quickSort( left );
let rightSorted = quickSort( right );
return [ ...leftSorted, pivot, ...rightSorted ];
}
//-------------------------------------------
//-------------------------------------------
binarySearch( [ 5, 10, 12, 15, 20, 30, 70 ], 12 ); // => true
binarySearch( [ 5, 10, 12, 15, 20, 30, 70 ], 24 ); // => false
//-------------------------------------------
//-------------------------------------------
function binarySearch( array, target ) {
if ( array.length === 0 ) {
return false;
}
//...some code here
}
//-------------------------------------------
//-------------------------------------------
function binarySearch( array, target ) {
if ( array.length === 0 ) {
return false;
}
let midIdx = Math.floor( array.length / 2 );
let leftHalf = array.slice( 0, midIdx );
let rightHalf = array.slice( midIdx + 1 );
//...some code here
}
//-------------------------------------------
//-------------------------------------------
function binarySearch( array, target ) {
if ( array.length === 0 ) {
return false;
}
let midIdx = Math.floor( array.length / 2 );
let leftHalf = array.slice( 0, midIdx );
let rightHalf = array.slice( midIdx + 1 );
if ( target < array[ midIdx ] ) {
return binarySearch( leftHalf, target );
} else if ( target > array[ midIdx ] ) {
return binarySearch( rightHalf, target );
}
//...some code here
}
//-------------------------------------------
//-------------------------------------------
function binarySearch( array, target ) {
if ( array.length === 0 ) {
return false;
}
let midIdx = Math.floor( array.length / 2 );
let leftHalf = array.slice( 0, midIdx );
let rightHalf = array.slice( midIdx + 1 );
if ( target < array[ midIdx ] ) {
return binarySearch( leftHalf, target );
} else if ( target > array[ midIdx ] ) {
return binarySearch( rightHalf, target );
} else {
return true;
}
}
//-------------------------------------------
//-------------------------------------------
function binarySearch( array, target ) {
if ( array.length === 0 ) {
return false;
}
let midIdx = Math.floor( array.length / 2 );
let leftHalf = array.slice( 0, midIdx );
let rightHalf = array.slice( midIdx + 1 );
if ( target < array[ midIdx ] ) {
return binarySearch( leftHalf, target );
} else if ( target > array[ midIdx ] ) {
return binarySearch( rightHalf, target );
} else {
return true;
}
}
//-------------------------------------------
//-------------------------------------------
function factorial( n ) {
if ( n === 1 ) return 1;
return n * factorial( n - 1 );
}
factorial( 6 ); // => 720, requires 6 calls
factorial( 6 ); // => 720, requires 6 calls
factorial( 5 ); // => 120, requires 5 calls
factorial( 7 ); // => 5040, requires 7 calls
//-------------------------------------------
//-------------------------------------------
function factorial( n ) {
// if we have calculated factorial(n) previously, fetch the stored result in memo
if ( n in memo ) return memo[ n ];
if ( n === 1 ) return 1;
// otherwise, we have not calculated factorial(n) previously, so calculate it now,
// but store the result in case we need it again in the future
memo[ n ] = n * factorial( n - 1 );
return memo[ n ];
}
//-------------------------------------------
//-------------------------------------------
factorial( 6 ); // => 720, requires 6 calls
factorial( 6 ); // => 720, requires 1 call
factorial( 5 ); // => 120, requires 1 call
factorial( 7 ); // => 5040, requires 2 calls
memo; // => { '2': 2, '3': 6, '4': 24, '5': 120, '6': 720, '7': 5040 }
//-------------------------------------------
//-------------------------------------------
function fib( n ) {
if ( n === 1 || n === 2 ) return 1;
return fib( n - 1 ) + fib( n - 2 );
}
//-------------------------------------------
//-------------------------------------------
function fastFib( n, memo = {} ) {
if ( n in memo ) return memo[ n ];
if ( n === 1 || n === 2 ) return 1;
memo[ n ] = fastFib( n - 1, memo ) + fastFib( n - 2, memo );
return memo[ n ];
}
//-------------------------------------------
//-------------------------------------------
// fib(0); // => 0
// fib(1); // => 1
// fib(2); // => 1
// fib(6); // => 8
// fib(7); // => 13
//-------------------------------------------
//-------------------------------------------
function tabulatedFib( n ) {
// create a blank array of length `n`
let table = new Array( n );
// seed the first two values
table[ 0 ] = 0;
table[ 1 ] = 1;
// complete the table by moving from left to right,
// following the fibonacci pattern
for ( let i = 2; i <= n; i++ ) {
table[ i ] = table[ i - 1 ] + table[ i - 2 ];
}
return table[ n ];
}
//-------------------------------------------
//-------------------------------------------
function fib( n ) {
if ( n === 0 ) return 0;
if ( n === 1 ) return 1;
let secondLast = 0;
let last = 1;
for ( let i = 2; i <= n; i++ ) {
let temp = last;
last = last + secondLast;
secondLast = temp;
}
return last;
}
//-------------------------------------------
//-------------------------------------------
class Node {
constructor( val ) {
this.value = val;
this.next = null;
}
}
class Stack {
constructor() {
this.top = null;
this.bottom = null;
this.length = 0;
}
push( val ) {
const newNode = new Node( val );
if ( !this.top ) {
this.top = newNode;
this.bottom = newNode;
} else {
const temp = this.top;
this.top = newNode;
this.top.next = temp;
}
return ++this.length;
}
pop() {
if ( !this.top ) {
return null;
}
const temp = this.top;
if ( this.top === this.bottom ) {
this.bottom = null;
}
this.top = this.top.next;
this.length--;
return temp.value;
}
size() {
return this.length;
}
}
//-------------------------------------------
//-------------------------------------------
class Node {
constructor( val ) {
this.value = val;
this.next = null;
}
}
class Queue {
constructor() {
this.front = null;
this.back = null;
this.length = 0;
}
enqueue( val ) {
const newNode = new Node( val );
if ( !this.front ) {
this.front = newNode;
this.back = newNode;
} else {
this.back.next = newNode;
this.back = newNode;
}
return ++this.length;
}
dequeue() {
if ( !this.front ) {
return null;
}
const temp = this.front;
if ( this.front === this.back ) {
this.back = null;
}
this.front = this.front.next;
this.length--;
return temp.value;
}
size() {
return this.length;
}
}
//-------------------------------------------
//-------------------------------------------
class TreeNode {
constructor( val ) {
this.val = val;
this.left = null;
this.right = null;
}
}
Constructing a tree is a matter of creating the nodes and setting `left`
and `right`
however we please.For example:
let a = new TreeNode( 'a' );
let b = new TreeNode( 'b' );
let c = new TreeNode( 'c' );
let d = new TreeNode( 'd' );
let e = new TreeNode( 'e' );
let f = new TreeNode( 'f' );
a.left = b;
a.right = c;
b.left = d;
b.right = e;
c.right = f;
//-------------------------------------------
//-------------------------------------------
function inOrderPrint( root ) {
if ( root === null ) return;
//...some code here
}
//-------------------------------------------
//-------------------------------------------
function inOrderPrint( root ) {
if ( !root ) return;
inOrderPrint( root.left );
console.log( root.val );
inOrderPrint( root.right );
}
Given our tree, `inOrderPrint`
would print the values in the order: `d, b, e, a, c, f`
In - Order has the pattern of left, self, right.This means:
-a node can only be printed once it 's left subtree has been completely printed. -
a node 's right subtree can only be printed once the node itself has been printed.
# # Pre - Order
Given the root of a tree, the steps
for `preOrderPrint`
are:
-print root -
print all nodes in the left subtree -
print all nodes in the right subtree
Translating this into code:
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
function postOrderPrint( root ) {
if ( !root ) return;
postOrderPrint( root.left );
postOrderPrint( root.right );
console.log( root.val );
}
//-------------------------------------------
//-------------------------------------------
function inOrderPrint( root ) {
if ( !root ) return;
inOrderPrint( root.left );
console.log( root.val );
inOrderPrint( root.right );
}
//-------------------------------------------
//-------------------------------------------
class TreeNode {
constructor( val ) {
this.val = val;
this.left = null;
this.right = null;
}
}
class BST {
constructor() {
this.root = null;
}
insert( val, root = this.root ) {
if ( !this.root ) {
this.root = new TreeNode( val );
return;
}
if ( val < root.val ) {
if ( !root.left ) {
root.left = new TreeNode( val );
} else {
this.insert( val, root.left );
}
} else {
if ( !root.right ) {
root.right = new TreeNode( val );
} else {
this.insert( val, root.right );
}
}
}
}
//-------------------------------------------
//-------------------------------------------
class BST {
constructor() {
// initialize the tree to be empty
this.root = null;
}
insert( val, root = this.root ) {
// if the tree is currently empty, then create the node as the 'absolute' root
if ( !this.root ) {
this.root = new TreeNode( val );
return;
}
// otherwise, the tree is not empty, so...
// if our val to insert is less than the root...
if ( val < root.val ) {
if ( !root.left ) { //...some code hereand the left child does not exist,
root.left = new TreeNode( val ); // then create the node as the left child
} else { //...some code hereand the left child already exists,
this.insert( val, root.left ); // then recursively insert on the left subtree
}
// if our val to insert is greater than or equal to the root...
} else {
if ( !root.right ) { // ...and the right child does not exist,
root.right = new TreeNode( val ); // then create the node as the right child
} else { // ...and the right child already exists,
this.insert( val, root.right ); // then recursively insert on the right subtree
}
}
}
}
// We can call `insert`
// to build up the `BST`
// without worrying about breaking the search tree property.Let 's build two different trees:
let tree1 = new BST();
tree1.insert( 10 );
tree1.insert( 5 );
tree1.insert( 16 );
tree1.insert( 1 );
tree1.insert( 7 );
tree1.insert( 16 );
let tree2 = new BST();
tree2.insert( 1 );
tree2.insert( 5 );
tree2.insert( 7 );
tree2.insert( 10 );
tree2.insert( 16 );
tree2.insert( 16 );
//-------------------------------------------
//-------------------------------------------
let tree = new BST();
tree.insert( 10 );
tree.insert( 5 );
tree.insert( 16 );
tree.insert( 1 );
tree.insert( 7 );
tree.insert( 16 );
tree.search( 7 ); // => true
tree.search( 16 ); // => true
tree.search( 14 ); // => false
//-------------------------------------------
//-------------------------------------------
class BST {
//...some code here
search( val, root = this.root ) {
if ( !root ) return false;
if ( val < root.val ) {
return this.search( val, root.left );
} else if ( val > root.val ) {
return this.search( val, root.right );
} else {
return true;
}
}
}
// assuming our BST class from the previous section
class BST {
//...some code here
// commented
search( val, root = this.root ) {
// if the tree is empty, then the target val is not in the tree, so return false
if ( !root ) return false;
// otherwise the tree is not empty, so...
if ( val < root.val ) {
// if the target is less than the root,
// then search the left subtree
return this.search( val, root.left );
} else if ( val > root.val ) {
// if the target is greater than the root,
// then search the right subtree
return this.search( val, root.right );
} else {
// otherwise, the target must be equal to the root
// so return true since we found it!
return true;
}
}
}
//-------------------------------------------
//-------------------------------------------
function depthFirst( root ) {
let stack = [ root ];
while ( stack.length ) {
let node = stack.pop();
console.log( node.val );
if ( node.right ) stack.push( node.right );
if ( node.left ) stack.push( node.left );
}
}
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
function depthFirstRecur( root ) {
if ( !root ) return;
console.log( root.val );
depthFirstRecur( root.left );
depthFirstRecur( root.right );
}
//-------------------------------------------
//-------------------------------------------
function breadthFirst( root ) {
let queue = [ root ];
while ( queue.length ) {
let node = queue.shift();
console.log( node.val );
if ( node.left ) queue.push( node.left );
if ( node.right ) queue.push( node.right );
}
}
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
//-------------------------------------------
class GraphNode {
constructor( val ) {
this.val = val;
this.neighbors = [];
}
}
let a = new GraphNode( "a" );
let b = new GraphNode( "b" );
let c = new GraphNode( "c" );
let d = new GraphNode( "d" );
let e = new GraphNode( "e" );
let f = new GraphNode( "f" );
a.neighbors = [ b, c, e ];
c.neighbors = [ b, d ];
e.neighbors = [ a ];
f.neighbors = [ e ];
//-------------------------------------------
//-------------------------------------------
class GraphNode {
constructor( val ) {
this.val = val;
this.neighbors = [];
}
}
let a = new GraphNode( "a" );
let b = new GraphNode( "b" );
let c = new GraphNode( "c" );
let d = new GraphNode( "d" );
let e = new GraphNode( "e" );
let f = new GraphNode( "f" );
a.neighbors = [ e, c, b ];
c.neighbors = [ b, d ];
e.neighbors = [ a ];
f.neighbors = [ e ];
//-------------------------------------------
//-------------------------------------------
function depthFirstRecur( node ) {
console.log( node.val );
node.neighbors.forEach( ( neighbor ) => {
depthFirstRecur( neighbor );
} );
}
//-------------------------------------------
//-------------------------------------------
function depthFirstRecur( node, visited = new Set() ) {
// if this node has already been visited, then return early
if ( visited.has( node.val ) ) return;
// otherwise it hasn't yet been visited,
// so print it's val and mark it as visited.
console.log( node.val );
visited.add( node.val );
// then explore each of its neighbors
node.neighbors.forEach( neighbor => {
depthFirstRecur( neighbor, visited );
} );
}
//-------------------------------------------
//-------------------------------------------
function depthFirstIter( node ) {
let visited = new Set();
let stack = [ node ];
while ( stack.length ) {
let node = stack.pop();
// if this node has already been visited, then skip this node
if ( visited.has( node.val ) ) continue;
// otherwise it hasn't yet been visited,
// so print it's val and mark it as visited.
console.log( node.val );
visited.add( node.val );
// then add its neighbors to the stack to be explored
stack.push( ...node.neighbors );
}
}
//-------------------------------------------
//-------------------------------------------
let graph = {
'a': [ 'b', 'c', 'e' ],
'b': [],
'c': [ 'b', 'd' ],
'd': [],
'e': [ 'a' ],
'f': [ 'e' ]
};
//-------------------------------------------
//-------------------------------------------
function depthFirstRecur( node, graph, visited = new Set() ) {
if ( visited.has( node ) ) return;
console.log( node );
visited.add( node );
graph[ node ].forEach( ( neighbor ) => {
depthFirstRecur( neighbor, graph, visited );
} );
}
//-------------------------------------------
//-------------------------------------------
function depthFirst( graph ) {
let visited = new Set();