fix: make fmod take the correct amount of parameters#535
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The previous version of the std::math::fmod function only took one argument which was incorrect and rendered the function impossible to use. This patch fixes this issue by making the std::math::fmod function take 2 arguments (numerator and denominator) so the remainder of the division can be effectively calculated.
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The previous version of the std::math::fmod function only took one argument which was incorrect and rendered the function impossible to use.
This patch fixes this issue by making the std::math::fmod function take 2 arguments (numerator and denominator) so the remainder of the division can be effectively calculated.