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Adjacent bit counts
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73 lines (72 loc) · 1.39 KB
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code in c++ *****************************************************
#include <iostream>
using namespace std;
typedef long long ll;
#define m 1000000007
ll dp[101][101][2];
ll f(int n, int k, int start)
{
if (dp[n][k][start] >= 0)
{
return dp[n][k][start];
}
if (n == 1)
{
if (k == 0)
{
dp[n][k][start] = 1;
return 1;
}
else
{
dp[n][k][start] = 0;
return 0;
}
}
if (k < 0)
{
dp[n][k][start] = 0;
return 0;
}
if (start == 1)
{
ll sum1 = f(n - 1, k - 1, 1);
ll sum2 = f(n - 1, k, 0);
dp[n][k][start] = (sum1 + sum2) % m;
}
else
{
ll sum1 = f(n - 1, k, 1) % m;
ll sum2 = f(n - 1, k, 0) % m;
dp[n][k][start] = (sum1 + sum2) % m;
}
return dp[n][k][start];
}
ll adjbc(int n, int k)
{
ll sum1 = f(n, k, 1) % m;
ll sum2 = f(n, k, 0) % m;
return (sum1 + sum2) % m;
}
int main()
{
int p;
cin >> p;
for (int i = 0; i <= 101; i++)
{
for (int j = 0; j <= 101; j++)
{
for (int k = 0; k < 2; k++)
{
dp[i][j][k] = -1;
}
}
}
while (p--)
{
int dataset_number, n, k;
cin >> dataset_number >> n >> k;
cout << dataset_number << " " << adjbc(n, k) << endl;
}
return 0;
}