-
Notifications
You must be signed in to change notification settings - Fork 12
Expand file tree
/
Copy path1221-split-a-string-in-balanced-strings.py
More file actions
41 lines (35 loc) · 1.09 KB
/
1221-split-a-string-in-balanced-strings.py
File metadata and controls
41 lines (35 loc) · 1.09 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
"""
Problem Link: https://leetcode.com/problems/split-a-string-in-balanced-strings/
Balanced strings are those who have equal quantity of 'L' and 'R' characters.
Given a balanced string s split it in the maximum amount of balanced strings.
Return the maximum amount of splitted balanced strings.
Example 1:
Input: s = "RLRRLLRLRL"
Output: 4
Explanation: s can be split into "RL", "RRLL", "RL", "RL", each substring contains
same number of 'L' and 'R'.
Example 2:
Input: s = "RLLLLRRRLR"
Output: 3
Explanation: s can be split into "RL", "LLLRRR", "LR", each substring contains same
number of 'L' and 'R'.
Example 3:
Input: s = "LLLLRRRR"
Output: 1
Explanation: s can be split into "LLLLRRRR".
Example 4:
Input: s = "RLRRRLLRLL"
Output: 2
Explanation: s can be split into "RL", "RRRLLRLL", since each substring contains
an equal number of 'L' and 'R'
Constraints:
1 <= s.length <= 1000
s[i] = 'L' or 'R'
"""
class Solution:
def balancedStringSplit(self, s: str) -> int:
count = res = 0
for c in s:
count += 1 if c == 'L' else -1
res += count == 0
return res