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Feb_28.cpp
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88 lines (78 loc) · 2.11 KB
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/*
Question:
Implement FreqStack, a class which simulates the operation of a stack-like data structure.
FreqStack has two functions:
push(int x), which pushes an integer x onto the stack.
pop(), which removes and returns the most frequent element in the stack.
If there is a tie for most frequent element, the element closest to the top of the stack is removed and returned.
Example 1:
Input:
["FreqStack","push","push","push","push","push","push","pop","pop","pop","pop"],
[[],[5],[7],[5],[7],[4],[5],[],[],[],[]]
Output: [null,null,null,null,null,null,null,5,7,5,4]
Explanation:
After making six .push operations, the stack is [5,7,5,7,4,5] from bottom to top. Then:
pop() -> returns 5, as 5 is the most frequent.
The stack becomes [5,7,5,7,4].
pop() -> returns 7, as 5 and 7 is the most frequent, but 7 is closest to the top.
The stack becomes [5,7,5,4].
pop() -> returns 5.
The stack becomes [5,7,4].
pop() -> returns 4.
The stack becomes [5,7].
*/
#include<iostream>
using namespace std;
#include <set>
#include <string>
#include <bits/stdc++.h>
#include <vector>
#include <unordered_map>
class FreqStack {
public:
unordered_map<int,int>occ;
vector<int>v;
vector<int>:: iterator it;
FreqStack() {
occ.clear();
v.clear();
}
void push(int x) {
v.push_back(x);
occ[x]++;
}
int most_occurance_ele()
{
int ma=0,d;
for(auto e:occ)
{
if(e.second>ma)
{
ma=e.second;
d=e.first;
}
}
return d;
}
int pop()
{
int ele=most_occurance_ele(),y;
for(auto it=v.rbegin();it < v.rend();it++)
{
if(occ[*(it)] == occ[ele])
{
y=*(it);
v.erase((it + 1) .base());
break;
}
}
occ[y]--;
return y;
}
};
/**
* Your FreqStack object will be instantiated and called as such:
* FreqStack* obj = new FreqStack();
* obj->push(x);
* int param_2 = obj->pop();
*/