Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head.
Input: head = [1,2,6,3,4,5,6], val = 6
Output: [1,2,3,4,5]
Time: O(n)
Space: O(1)
public ListNode removeElements(ListNode head, int val) {
ListNode dummy = new ListNode(0, head);
ListNode prev = dummy;
while (head != null) {
if (head.val == val)
prev.next = head.next;
else
prev = head;
head = head.next;
}
return dummy.next;
}