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Integer from a Base 16 String

If you have a String which contains text that can be interpreted as a base 16 integer, you can convert it into an int by using parseInt and giving the number 16 as an extra argument.

~void main() {
String text = "C";

int twelve = Integer.parseInt(text, 16);

IO.println(twelve);
~}

This will not work if the number is prefixed by 0x like it would be in your code.

~void main() {
Integer.parseInt("0xC", 16);
~}

If you want to handle both hexadecimal numbers and regular base 10 numbers you should instead use Integer.decode.

~void main() {
IO.println(Integer.decode("0xC"));
IO.println(Integer.decode("0x19"));
IO.println(Integer.decode("19"));
~}