11-Grading_Students.md

Problem

HackerLand University has the following grading policy:

• Every Student receives a grade in the inclusive range from 0 to 100.
• Any grade less than 40 is a failing grade.

Sam is a professor at the university and likes to round each student's grade according to these rules:

• If the difference between the grade and the next multiple of 5 is less than 3, round grade up to the next multiple of 5.
• If the value of grade is less than 38, no rounding occurs as the results will still be a failing grade.

Examples

• grade = 84 round to 85 (85 - 84 is less than 3)
• grade = 29 do not round (result is less than 40)
• grade = 57 do not round (60 - 57 is 3 or higher)

Given the initial value of grade for each of Sam's n students, write code to automate the rounding process.

Function description

Complete the function gradingStudents in the editor below.

gradingStudents has the following parameter(s):

• int grades[n]: the grades before rounding

Returns

• int[n]: the grades after rounding as appropriate

Input Format

The first line contains a single integer, n, the number of students. Each line i of the n subsequent lines contains a single integer, grades[i].

Constraints

• 1 <= n <= 60
• 0 <= grades[i] <= 100

Sample Input 0

4
73
67
38
33

Sample Output 0

75
67
40
33

Explanation 0

| ID | Original Grade | Final Grade | | -- - -------------- | ----------- | | 1 | 73 | 75 | | 2 | 67 | 67 | | 3 | 38 | 40 | | 4 | 33 | 33 |

1. Student 1 received a 73, and the next multiple of 5 from 73 is 75. Since 75 - 73 < 3, the student's grade is rounded to 75.
2. Student 2 received a 67, and the next multiple of 5 from 67 is 70. Since 70 - 67 = 3, the grade will not be modified and the student's final grade is 67.
3. Student 3 received a 38, and the next multiple of 5 from 38 is 40. Since 40 - 38 < 3, the student's grade will be rounded to 40.
4. Student 4 received a grade below 33, so the grade will not be modified and the student's final grade is 33.