fix: use variable symbol instead of arrow function symbol for default export check

Fixed an issue where arrow function default export detection was checking
the arrow function's symbol instead of the variable declaration's symbol.

🤖 Generated with [Claude Code](https://claude.com/claude-code)

Co-Authored-By: Claude <noreply@anthropic.com>

Author: angrychow

ts-parser/src/parser/FunctionParser.ts

@@ -386,7 +386,8 @@ export class FunctionParser {
       isExported = true;
     } else {
       const parent = varDecl.getVariableStatement();
-      isExported = parent ? (parent.isExported() || parent.isDefaultExport() || (this.defaultExportSymbol === arrowFunc.getSymbol() && this.defaultExportSymbol !== undefined)) : false;
+      const varSymbol = varDecl.getSymbol();
+      isExported = parent ? (parent.isExported() || parent.isDefaultExport() || (this.defaultExportSymbol === varSymbol && this.defaultExportSymbol !== undefined)) : false;
     }
 
     return {

ts-parser/test-repo/src/test-export-default.ts

@@ -0,0 +1,11 @@
+// 测试用例:箭头函数先声明,然后作为默认导出
+const foo = () => {
+  console.log('bar')
+}
+
+export default foo;
+
+// 对比:直接导出的箭头函数
+export const bar = () => {
+  console.log('baz')
+}