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Copy path73_SetMatrixZeroes.py
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83 lines (67 loc) · 2.31 KB
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# coding: utf8
"""
题目链接: https://leetcode.com/problems/set-matrix-zeroes/description.
题目描述:
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
click to show follow up.
Follow up:
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
"""
class Solution(object):
def setZeroes_v1(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
if not matrix:
return
rows = len(matrix)
columns = len(matrix[0])
zero_rows = [0 for _ in range(rows)]
zero_columns = [0 for _ in range(columns)]
for i in range(rows):
for j in range(columns):
if not matrix[i][j]:
zero_rows[i] = 1
zero_columns[j] = 1
for i in range(rows):
for j in range(columns):
if zero_rows[i] or zero_columns[j]:
matrix[i][j] = 0
def setZeroes_v2(self, matrix):
"""
:type matrix: List[List[int]]
:rtype: void Do not return anything, modify matrix in-place instead.
"""
if not matrix:
return
rows = len(matrix)
columns = len(matrix[0])
zero_first_row = 0
zero_first_column = 0
for j in range(columns):
if not matrix[0][j]:
zero_first_row = 1
break
for i in range(rows):
if not matrix[i][0]:
zero_first_column = 1
break
for i in range(1, rows):
for j in range(1, columns):
if not matrix[i][j]:
matrix[0][j] = 0
matrix[i][0] = 0
for i in range(1, rows):
for j in range(1, columns):
if not matrix[0][j] or not matrix[i][0]:
matrix[i][j] = 0
if zero_first_row:
for j in range(columns):
matrix[0][j] = 0
if zero_first_column:
for i in range(rows):
matrix[i][0] = 0