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Copy path24_SwapNodesInPairs.py
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50 lines (36 loc) · 1.1 KB
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# coding: utf8
"""
题目链接: https://leetcode.com/problems/swap-nodes-in-pairs/description.
题目描述:
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be
changed.
"""
# Definition for singly-linked list.
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
def __repr__(self):
return 'val: {0}'.format(self.val)
class Solution(object):
def swapPairs(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
if not head or not head.next:
return head
cursor = head
pre = ListNode(0)
head = head.next
while cursor and cursor.next:
n = cursor.next
cursor.next = n.next
n.next = cursor
pre.next = n
pre = cursor
cursor = cursor.next
return head