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71 lines (58 loc) · 1.58 KB
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# coding: utf8
"""
题目链接: https://leetcode.com/problems/binary-tree-level-order-traversal/description.
题目描述:
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by
level).
For example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its level order traversal as:
[
[3],
[9,20],
[15,7]
]
"""
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def levelOrder(self, root):
"""
:type root: TreeNode
:rtype: List[List[int]]
"""
if not root:
return []
queue = []
ans = []
# 非递归解法
# 模拟队列, 辅助变量: 记录队列头尾节点
front = 0
rear = 1
queue.append(root)
while front < rear:
# 记录上一层节点数
last = rear
level = []
while front < last:
root = queue[front]
level.append(root.val)
front += 1
# 左右子树入队
if root.left:
queue.append(root.left)
rear += 1
if root.right:
queue.append(root.right)
rear += 1
ans.append(level)
return ans