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Copy path108_ConvertSortedArrayToBinarySearchTree.py
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56 lines (39 loc) · 1.43 KB
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# coding: utf8
"""
题目链接: https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description.
题目描述:
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees
of every node never differ by more than 1.
Example:
Given the sorted array: [-10,-3,0,5,9],
One possible answer is: [0,-3,9,-10,null,5], which represents the following height balanced BST:
0
/ \
-3 9
/ /
-10 5
"""
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def sortedArrayToBST(self, nums):
"""
:type nums: List[int]
:rtype: TreeNode
"""
return self.construct_binary_search_tree(nums, 0, len(nums) - 1)
# 二分, 递归建立二叉搜索树
def construct_binary_search_tree(self, nums, nl, nr):
if nl > nr:
return None
mid = nl + (nr - nl) / 2
left = self.construct_binary_search_tree(nums, nl, mid - 1)
right = self.construct_binary_search_tree(nums, mid + 1, nr)
root = TreeNode(nums[mid])
root.left, root.right = left, right
return root