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Copy path173_BinarySearchTreeIterator.py
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59 lines (44 loc) · 1.36 KB
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# coding: utf8
"""
题目链接: https://leetcode.com/problems/binary-search-tree-iterator/description.
题目描述:
Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a
BST.
Calling next() will return the next smallest number in the BST.
Note: next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
Credits:
Special thanks to @ts for adding this problem and creating all test cases.
"""
# Definition for a binary tree node
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class BSTIterator(object):
def __init__(self, root):
"""
:type root: TreeNode
"""
self.stack = []
while root:
self.stack.append(root)
root = root.left
def hasNext(self):
"""
:rtype: bool
"""
return True if self.stack else False
def next(self):
"""
:rtype: int
"""
root = self.stack.pop()
right = root.right
while right:
self.stack.append(right)
right = right.left
return root.val
# Your BSTIterator will be called like this:
# i, v = BSTIterator(root), []
# while i.hasNext(): v.append(i.next())