This example demonstrates a classic use case for recursion to compute the factorial of a number. Let's break it down step by step.
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Factorial Concept: Factorial of a non-negative integer
n, denoted byn!, is the product of all positive integers less than or equal ton. For example:- (3! = 3 \times 2 \times 1 = 6)
- (4! = 4 \times 3 \times 2 \times 1 = 24) The factorial of 0 is defined to be 1, i.e., (0! = 1).
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Definition of
factorialFunction:func factorial(x int) int { if x == 1 { fmt.Println("x is 1 now") return 1 } else { fmt.Println("x is : ", x) return x * factorial(x-1) } }
The function is designed to compute the factorial of an integer
x. Here's how it works:- Base Case: If
xis 1, the function prints "x is 1 now" and returns 1 because (1! = 1). - Recursive Case: Otherwise, it prints the current value of
xand then makes a recursive call to compute the factorial ofx-1. The result of this recursive call is then multiplied byxto get the factorial ofx.
- Base Case: If
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Execution Flow: Calling
factorial(3)triggers the following flow:factorial(3) => 3 * factorial(2) => 3 * (2 * factorial(1)) => 3 * (2 * 1) => 6
The console output will be:
x is : 3 x is : 2 x is 1 now
These print statements show the order in which the function processes values of
x. The deepest level of recursion is reached whenxbecomes 1, after which the function starts returning values to the previous levels of the call stack. -
Final Output: In the
mainfunction, the result offactorial(3)(which is 6) gets printed, so the final output will be:x is : 3 x is : 2 x is 1 now 6
In summary, this code demonstrates a recursive approach to calculating the factorial of a number by breaking down the problem into smaller subproblems until a base case (when x is 1) is reached.
$ go run main.go
x is : 3
x is : 2
x is 1 now
6