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style: fix duplicate function definition and linting issues
1 parent 96688b3 commit cca120d

1 file changed

Lines changed: 4 additions & 81 deletions

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codeflash/discovery/functions_to_optimize.py

Lines changed: 4 additions & 81 deletions
Original file line numberDiff line numberDiff line change
@@ -411,7 +411,6 @@ def closest_matching_file_function_name(
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closest_match = function
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closest_file = file_path
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if closest_match is not None and closest_file is not None:
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return closest_file, closest_match
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return None
@@ -949,87 +948,11 @@ def filter_files_optimized(file_path: Path, tests_root: Path, ignore_paths: list
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)
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def _bounded_levenshtein(s1: str, s2: str, max_distance: int) -> int:
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"""Compute Levenshtein distance but stop when distance exceeds max_distance.
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Returns a value > max_distance when the true distance is > max_distance."""
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# Fast path equal
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if s1 == s2:
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return 0
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# Ensure s1 is the shorter
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if len(s1) > len(s2):
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s1, s2 = s2, s1
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n = len(s1)
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m = len(s2)
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# If length difference already exceeds max allowed distance, we can exit
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if m - n > max_distance:
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return max_distance + 1
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# Initialize previous row: distances from empty s2 prefix to s1 prefixes
974-
previous = list(range(n + 1))
975-
current = [0] * (n + 1)
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# We will only compute values within a "band" [start..end] for each row
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for i in range(1, m + 1):
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# Position in s2 is i (1-based for DP), character is s2[i-1]
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char2 = s2[i - 1]
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# Compute band boundaries (1-based indices for s1 positions)
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start = max(1, i - max_distance)
983-
end = min(n, i + max_distance)
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985-
# If start > end the band is empty -> distance exceeds max_distance
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if start > end:
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return max_distance + 1
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# Set current[0] for the empty prefix of s1
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current[0] = i
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# Fill left part outside band with large values
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for k in range(1, start):
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current[k] = max_distance + 1
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# Compute values inside the band
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for j in range(start, end + 1):
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if s1[j - 1] == char2:
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current[j] = previous[j - 1]
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else:
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# deletion = previous[j] + 1
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# insertion = current[j - 1] + 1
1003-
# substitution = previous[j - 1] + 1
1004-
a = previous[j] + 1
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b = current[j - 1] + 1
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c = previous[j - 1] + 1
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# Fast min of three
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t = a if a < b else b
1009-
current[j] = c if c < t else t
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# Fill right part outside band with large values
1012-
for k in range(end + 1, n + 1):
1013-
current[k] = max_distance + 1
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1015-
# Swap rows
1016-
previous, current = current, previous
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1018-
# Early exit: if the minimum value in the active band is greater than max_distance
1019-
# then the final distance must exceed max_distance
1020-
# (band width is small: at most 2*max_distance+1).
1021-
row_min = min(previous[start : end + 1])
1022-
if row_min > max_distance:
1023-
return max_distance + 1
1024-
1025-
return previous[n]
1026-
1027-
1028-
1029-
1030-
def _bounded_levenshtein(s1: str, s2: str, max_distance: int) -> int:
1031-
"""Compute Levenshtein distance but stop when distance exceeds max_distance.
1032-
Returns a value > max_distance when the true distance is > max_distance."""
954+
Returns a value > max_distance when the true distance is > max_distance.
955+
"""
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# Fast path equal
1034957
if s1 == s2:
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return 0
@@ -1080,8 +1003,8 @@ def _bounded_levenshtein(s1: str, s2: str, max_distance: int) -> int:
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b = current[j - 1] + 1
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c = previous[j - 1] + 1
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# Fast min of three
1083-
t = a if a < b else b
1084-
current[j] = c if c < t else t
1006+
t = min(b, a)
1007+
current[j] = min(t, c)
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10861009
# Fill right part outside band with large values
10871010
for k in range(end + 1, n + 1):

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